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lalodhi

hi require help can anyone help me plz ?
Using the 10.0.0.0/8 network, subnet the network to allow for 2040
usable subnets. Using subnet #1162, subnet the network to allow
for 30 usable subnets. Using your answer from the previous
calculation, subnet the subnet #18 to allow for 6 usable subnets.
Hint: if done correctly, the subnet mask that is required for any of
the final subnets will be a /27.

networker050184

Why don't you show us what you came up with and we can point you in the right direction. We aren't here to do your homework for you.

lalodhi

I have got
first useable address 10.0.0.1
last useable address 10.0.7.254
broadcast address 10.0.7.255
next network id 10.0.8.0/21
i dont knw how i can solve it for subnet 1162 for 30 hosts.



10.0.0.1 - 10.0.7.254
10.0.7.255

lalodhi

the point im stucked is using subnet 1162 and 18. Plz guide me how to do it i will do it myself

Heero

For the first part, you are being asked to divide the 10.0.0.0/8 network into 2048 SUBNETS, not a single subnet with 2048 hosts.

lalodhi

Heero wrote: »

For the first part, you are being asked to divide the 10.0.0.0/8 into 2048 SUBNETS, not a single subnet with 2048 hosts.

no one agree to help me. its been a day i havnt got such a clue to get it solve.
anyway special thanks to heero for guiding me in right direction.

Scorp6

The formula required is 2^n-2 where n is number of bits borrowed for either subnets or hosts. In this case 2^11 gives you 2048 which is as close as you can get to your requirement of 2040 subnets. This yields a subnet mask of /19 or 255.255.224.0 for your required 2040 subnets. I will let you continue from there.