subnetting question

alien 1

1. Given the following host IP addresses 172.16.20.36/28:

(i) What is the subnet mask (in decimal) for this network?
(ii) How many bits have been borrowed to create this subnet?
(iii) What is its network address of this subnet?
(iv) What is the network broadcast address
(v) What is the usable host address range for this network?
(vi) How many usable host addresses are on this networks?

are these answers correct?

(i) 255.255.255.240
(ii) 4
(iii) 172.16.20.32 \28
(iv) 172.168.20.47 \28
(v) 172.16.20.33--->172.16.20.46
(vi) 14

thanks

Switch1

alien 1 wrote: »

1. Given the following host IP addresses 172.16.20.36/28:

(i) What is the subnet mask (in decimal) for this network?
(ii) How many bits have been borrowed to create this subnet?
(iii) What is its network address of this subnet?
(iv) What is the network broadcast address
(v) What is the usable host address range for this network?
(vi) How many usable host addresses are on this networks?

are these answers correct?

(i) 255.255.255.240
(ii) 4
(iii) 172.16.20.32 \28
(iv) 172.168.20.47 \28
(v) 172.16.20.33--->172.16.20.46
(vi) 14

thanks

All seem correct besides answer 2.

How many bits have been borrowed to create this subnet?
172.16.20.36 is a Class B address.
Class B addresses have 16 network bits.
11111111.11111111.00000000.00000000
255.255.0.0


/28 = 255.255.255.240
11111111.11111111.11111111.11110000

We have borrowed 12 host bits from the class B address.