agtjamesb007 wrote: » How do you know what addresses are included in a given summary?
theodoxa wrote: » 192.168.0.0/24192.168.1.0/24 192.168.2.0/24 192.168.3.0/24 192.168.4.0/24192.168.5.0/2411000000.10101000.00000000.0000000011000000.10101000.00000001.0000000011000000.10101000.00000010.0000000011000000.10101000.00000011.0000000011000000.10101000.00000100.0000000011000000.10101000.00000101.00000000 11000000.10101000.00000000.00000000 You could summarize the 6 networks to 192.168.0.0/21 (24 - 3 = 21), but the subnets with a 3rd octet ending in 110 and 111 were not given yet would be included in the summary. The solution to not include those subnets would be 2 summaries11000000.10101000.00000000.0000000011000000.10101000.00000001.0000000011000000.10101000.00000010.0000000011000000.10101000.00000011.00000000 11000000.10101000.00000000.00000000 (192.168.0.0/22) and11000000.10101000.00000100.0000000011000000.10101000.00000101.00000000 11000000.10101000.00000100.00000000 (192.168.4.0/23) Notice that for both summaries the bits added to the host portion include all combinations from all zeroes to all ones. (00, 01, 10, 11). This means that no additional [unwanted] subnets would be included in the summary.
Hondabuff wrote: » This is 100% correct. I would still rather have the one LSA of a /21 being advertised instead of 2 LSA's in the real world.