VLSM Question help
2URGSE
Member Posts: 220 ■■■□□□□□□□
in CCNA & CCENT
Objective:
Given 172.16.8.0/22, divide the network so the following are requirements are met:
Sales Department needs 300 hosts.
Marketing Department needs 76 hosts.
Administration Department needs 24 hosts.
HR Department needs 12 hosts.
Accounting Department needs 5 hosts.
So I start with the Sales Department.
(2^n)-2 = 300
When n=9, the max number of hosts is 510, so that will satisfy the 300 hosts Sales needs.
Next I take 32-9= 23, so the mask for the Sales subnet is /23.
Now comes the part that I get lost and need help.
I'm trying to find the first host address and last host address.
The first host address is 172.16.8.1, the last host address is 172.16.9.254. I get that part.
Next is the Marketing Department. (2^n)-2 = 76, so n=7 to satisfy this requirement.
This subnet is 172.16.10.0. Can someone please shed some light on how the got to that subnet?
The next subnet is 172.16.10.128, how did they get there?
* Please no binary stuff, I don't use it in my studies, and surely not on the exam.
Given 172.16.8.0/22, divide the network so the following are requirements are met:
Sales Department needs 300 hosts.
Marketing Department needs 76 hosts.
Administration Department needs 24 hosts.
HR Department needs 12 hosts.
Accounting Department needs 5 hosts.
So I start with the Sales Department.
(2^n)-2 = 300
When n=9, the max number of hosts is 510, so that will satisfy the 300 hosts Sales needs.
Next I take 32-9= 23, so the mask for the Sales subnet is /23.
Now comes the part that I get lost and need help.
I'm trying to find the first host address and last host address.
The first host address is 172.16.8.1, the last host address is 172.16.9.254. I get that part.
Next is the Marketing Department. (2^n)-2 = 76, so n=7 to satisfy this requirement.
This subnet is 172.16.10.0. Can someone please shed some light on how the got to that subnet?
The next subnet is 172.16.10.128, how did they get there?
* Please no binary stuff, I don't use it in my studies, and surely not on the exam.
A+
Network+
CCENT (formally CCNA certified)
ICE (Imprivata Certified Engineer)
Network+
CCENT (formally CCNA certified)
ICE (Imprivata Certified Engineer)
Comments
-
diffie
Member Posts: 13 ■□□□□□□□□□
It’s been awhile for me but without using binary, 172.16.10.0 and 172.16.10.128, are simply the next usable addresses with the range 172.16.8.0/22
Your starting subnet is 172.16.8.0/22, which provides the range 172.16.8.1 - 172.16.11.254.
Your calculations so far are on point, for Sales you'd use 172.16.10.0/25 which would allow hosts in the range 172.16.8.1 to 172.16.9.254.
172.16.9.255 is the broadcast address for that range. The very next address would be 172.16.10.0
Your next calculations:
(2^h) - 2 = hosts
(2^7) - 2 = 126
h = 7
32 - 7 = 25
172.16.10.0/25 the usable range is 172.16.10.1 - 172.16.10.126
172.16.10.127 would be the broadcast address, 172.16.10.128 would be the next address.
Then, just keep going.
172.16.10.128/27 - 30 hosts/24 needed - 172.16.10.129 - 172.16.10.158, broadcast 172.16.10.159
172.16.10.160/28 - 14 hosts/12 needed - 172.16.10.161 - 172.16.10.174, broadcast 172.16.10.175
172.16.10.176/29 - 6 hosts/5 needed - 172.16.10.177 - 172.16.10.182, broadcast 172.16.10.183 -
Mr.Robot255
Member Posts: 196 ■■■□□□□□□□
i'm not great at explaining stuff but i will give it a go. (and hope i'm right)
300=/23 - /23 = 512 host
76=/25 - /25 = 128 host
24=/27 -/27 = 32 host
12=/28 -/28 =16 host
5=/29 -/29 =8 host
and we lose the first host and last host of each of them ,1st being Network I.D and last host being Broadcast.
so from 172.16.8.0 /22
the first block of 300 hosts will take 512 hosts a /23 as the its the nearest match bringing it to
172.16.8.0 - 172.16.9.255 /23
next block will then start from 172.16.10.0
so we then have
172.16.10.0 - 172.16.10.127 /25 (this covers our 76 hosts to nearest match/block size)
next will start as 172.16.10.128 - 172.16.10.159 /27
next will start as 172.16.10.160.............................
Something i use>
This is the chart i use for subnetting if you look for a /27 directly below it u see it will see it is for class C -255.255.224.0 and directly under the 224 is 32 for your block size which then will directly map to 8 subnets.
The mapping works like this using the bottom row we can say host and subnets
255 to the 1 (255 hosts to 1 subnet)
128 to the 2 (128 hosts to 2 subnets) etc
64 to the 4
32 to the 8
16 to 16
/25 ---/26 ----/27--- /28--- /29 ----/30
/31--- /32
0 - ----128--- -192
224 ----240---- 248
252
254 ----255
255 - -128
64
32
16
8
4
2
1
The quality isn't great but this is the video that made everything make sense to me.
https://www.youtube.com/watch?v=GSX1GlaznKM&t=41s
and part 2
https://www.youtube.com/watch?v=U9dVVIk8_zA&t=42s