DR election with graphic
Jeroen1000
Member Posts: 15 ■□□□□□□□□□
in CCNA & CCENT
Hello again
Still one thing that I got wrong. Worse is I do not know why
Following link leads to a word document, with the supposedly correct answer
http://jeroen.madoka.be/CCNA/graphic.doc
What I answered was:
RTD will be the DR of the 10.5.0.0/24 network
why?: Its E1 interface has the highest ip (10.7.0.1)
RTD will be the DR of the 10.4.0.0/24 network
why?: Its E1 interface has the highest ip (10.7.0.1)
RTB will be the DR of the 10.7.0.0/24 network
why?: Its E0 interface has the highest ip (10.7.0.2)
Unfortunately my exam is tomorrow and I am sure they'll ask a similar question
Thanks in advance for taking the time to look into this!
Still one thing that I got wrong. Worse is I do not know why
Following link leads to a word document, with the supposedly correct answer
http://jeroen.madoka.be/CCNA/graphic.doc
What I answered was:
RTD will be the DR of the 10.5.0.0/24 network
why?: Its E1 interface has the highest ip (10.7.0.1)
RTD will be the DR of the 10.4.0.0/24 network
why?: Its E1 interface has the highest ip (10.7.0.1)
RTB will be the DR of the 10.7.0.0/24 network
why?: Its E0 interface has the highest ip (10.7.0.2)
Unfortunately my exam is tomorrow and I am sure they'll ask a similar question
Thanks in advance for taking the time to look into this!
Comments
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hedhrts Member Posts: 74 ■■□□□□□□□□In addition, I would like to know why the election process takes place at all?
My studies have been interupted for almost a week. If memory serves (please bear with me, books not at hand yet), this has something to do with OSPF. I believe that are all point-to-point type links and the routers know that the election process isn't needed because there is only one neighbor on each link. -
deneb829 Member Posts: 292Good Topic for today - Election Day!There are only 10 types of people in this world - People who understand binary and people who do not.
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loboernesto Member Posts: 94 ■■□□□□□□□□It seems to be a tricky question because a first glance you think that the connections are point-to-pint in which case I would say that DR election doesn't take place in that graphic.
But looking carefully you can see that the interfaces are ethernet which means that the network type will be broadcast. (I've just check that on my home lab).
I would have chosen the same answers as you. What did the question say??. any other information? one possibility is that RTC has a router priority of 2 and RTB has router priority of 0 in which case the answers on the graphic are correct
cheers.
P.S: Can you put the entire question in your graphic?? -
DirtySouth Member Posts: 314 ■□□□□□□□□□I would like to see the entire question as well because the supposedly correct answers do not seem correct at all. Maybe I'm confused though.
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Jeroen1000 Member Posts: 15 ■□□□□□□□□□I've updated the word document with the question. It does not provide any more info though
It seems I found yet another mistake in the answers
PS: RTC will be the DR of 10.0.0.5 /24 because of the loopback interface.
This still does not explain why RTB is not the DR of 10.0.0.7/24 -
loboernesto Member Posts: 94 ■■□□□□□□□□PS: RTC will be the DR of 10.0.0.5 /24 because of the loopback interface.
This still does not explain why RTB is not the DR of 10.0.0.7/24
The loopback interface in RTC will be RTC RID but from what I know I don't think it will be the DR though since the loopback address (10.3.0.1) is lower than RTD E1 (10.7.0.1) interface address.
I think the question is wrong (the answers they give i mean). The good thing about these question is that they make you look into it and get to understand the concepts very well. The bad thing is that once you found a few of these questions and then you get 700/1000 in a practice exam you start thinking that most of the questions in these exams are wrong
cheers -
Arturasj Member Posts: 24 ■□□□□□□□□□Jeroen
Where did you find this question?
Just to make people aware of incorrect study materials.