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Cessation wrote: I believe it would be any multiple of 32 on the third octet. Because it is 255.255.224.0 that would match up to the 3rd bit which is 32. IE 1=128 2=192 (128+64) 3=224 (128+64+32) and so on. I hope this helps somewhat.
r_durant wrote: I don't mean to make it more confusing, but shouldn't the question have asked what are the valid subnet addresses? Unless the answers the question is seeking is 124.78.103.0, 126.78.48.0 and 186.211.100.0, which are valid host addresses if the mask is 255.255.224.0. (i think) 125.67.32.0, 125.78.160.0 and 176.55.96.0 are all valid subnet numbers, as indicated by Cessation. Unless it's me that is totally confused...
dbfield wrote: Thank you everyone for the clarification. I think sometimes I try to read too much into the question.
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