Calculating Network, Hosts, and Broadcast Adresses

verbala

Hey guys I'm taking a cisco exploration class at the moment and in the course its asking us to calculate the Network address, Hosts and Broadcast address from 189.1.119.53/23.

So from what I've been studying it seems like the network address would be 189.1.119.0... but according to the conversion tool the network address is actually 189.1.118.0.

Another aspect thats confusing to me aswell is the conversion tool also says the first usable host is 189.1.118.1. By my thinking I came up with 189.1.119.1...

Anyone have a good way of explaining this? This has been confusing the hell out of me lately

miller811

start here
http://www.techexams.net/forums/ccna-ccent/38772-subnetting-made-easy.html

amp2030

verbala wrote: »

Hey guys I'm taking a cisco exploration class at the moment and in the course its asking us to calculate the Network address, Hosts and Broadcast address from 189.1.119.53/23.

So from what I've been studying it seems like the network address would be 189.1.119.0... but according to the conversion tool the network address is actually 189.1.118.0.

Another aspect thats confusing to me aswell is the conversion tool also says the first usable host is 189.1.118.1. By my thinking I came up with 189.1.119.1...

Anyone have a good way of explaining this? This has been confusing the hell out of me lately

189.1.119.53/23

16 < 23 < 24 so interesting bit is third
24 - 23 = 1
2^1 = 2
118 < 119 < 120

189.1.118.0 subnet
189.1.118.1 first usable host
189.1.119.255 broadcast
189.1.119.254 last usable host

verbala

Thank you soo much for the fast reply!! I was so confused because it doesn't even mention subnetting in the program before asking that question.

Kaminsky

... my mistake

naruto007

PLSSS can you help me??? what is the answer for this
HOST IP ADDRESS 172.25.114.250
NETWORK MASK 255.255.0.0 (/16)

FIND:
NETWORK ADDRESS
BROADCAST ADDRESS
TOTAL NUMBER OF HOST BITS
NUMBER OF HOSTS

WITH FULL EXPLANATION PLSSS.......!

peanutnoggin

naruto007 wrote: »

PLSSS can you help me??? what is the answer for this
HOST IP ADDRESS 172.25.114.250
NETWORK MASK 255.255.0.0 (/16)

FIND:
NETWORK ADDRESS
BROADCAST ADDRESS
TOTAL NUMBER OF HOST BITS
NUMBER OF HOSTS

WITH FULL EXPLANATION PLSSS.......!

What are you not understanding about this question? It is pretty straight forward. If this is a homework assignment... which I'm assuming it is. You'd be better served to learn the material as opposed to someone just giving you the answer. Good luck!!

-Peanut

jojopramos

default subnet of /16 = Class B

Network Address = 172.25.0.0
Broadcast Address = 172.25.255.255
Number of Host Bits = 16
Number of Host = 65534

Please read more on IP Network Layer and Subnetting...

pcwiretechnologies

============================================
131.192.129.2/21(bits) 32(bits)-21(bits)=(11bits) (work with all the last 11 binaries)*

First convert all decimal to binary
10000011.11000000.10000 (001.00000010) (change all remaining to 0)*
.10000 (000.00000000)*


N 131.162.128.0

.10000 001.00000010 (change all remaining to 1)**
.10000 (111.11111111)**

B 131.162.135.255


.10000 001.00000010 (change all remaining to 0+last =1)***
.10000 (000.00000001)***
F 131.162.128.1

.10000 001.00000010 (change all remaining to 1 +last =0)****
.10000 (111.11111110)****
.(128+0+0+0+0+4+2+1=)135.(128+64+32+16+8+4+2+0=)254 confirmed!
L 131.162.135.254


============================================

eslaah

Thanks pcwiretechnologies little bit of your time has helped greatly i was looking every were but nothing made any sense. Your method helped alot thank you very much.