Explanation of the broadcast address of this network example

kctxaukctxau Posts: 130Member
Can someone explain how this is 31? I couldn't arrive at that number.
What is the broadcast address of the network 192.168.193.0/27?
Answer: 192.168.193.31
Chances are, once its explained, I'll say to myself "oh yeh, noooow I remember"
Thank-you, for your help.

Comments

  • gojericho0gojericho0 Posts: 1,060Member
    Do you know how to come up with the block size for that subnet mask?
  • amp2030amp2030 Posts: 253Member
    192.168.193.0/27
    24 < 27 < 32
    32 - 27 = 5
    2^5 = 32
    0 32 64 ...
    32 - 1 = 31
    192.168.193.31
  • dublinguydublinguy Posts: 22Member ■□□□□□□□□□
    kctxau wrote: »
    Can someone explain how this is 31? I couldn't arrive at that number.
    What is the broadcast address of the network 192.168.193.0/27?
    Answer: 192.168.193.31
    Chances are, once its explained, I'll say to myself "oh yeh, noooow I remember"
    Thank-you, for your help.

    I will calculate with the following method, As mask is 27, 32-27=5 , 2 ^5 = 32, So the block size is 32, now come to the ip

    192.168.193.0 , 32 is the number to add so next one should be
    192.168.193.32
    192.168.193.64

    192.168.193.0 - 192.168.193.31 (this is the broadbast address)
    192.168.193.1 - 192.168.193.30 (Is the valid host range)

    hope this helps, more details in the below link

    http://www.techexams.net/forums/ccna-ccent/38772-subnetting-made-easy.html
  • colink24colink24 Posts: 43Member ■■□□□□□□□□
    3 bits of the host portion so
    128+64+32 = 224
    256 - x = 224
    x = 32
    Network addresses 0 32 64 96 etc
  • kctxaukctxau Posts: 130Member
    Thanks for the replys. I arrived the 224 and had forgotten from there.
    So now I'll say to myself "oh yeh, noooow I remember"
    Again, thanks.
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