CIDR for private (172.16.0.0)

auos

Hi,
The private address (172.16.0.0/12) , it is mean the mask is (255.240.0.0) with range (172.16.0.0 - 172.31.255.255).

My question is :-
The mask (255.240.0.0) .......= 11111111.11110000.00000000.00000000
The address(172.31.255.255).= 10101100.11111000.11111111.11111111

how could the mask (240 with 4 bit) cover the rang (31 with 5 bit).


BR.

Nvermind

network 172.16.0.0
10101100.00010000.00000000.00000000
Subnet 255.240.0.0
11111111.11110000.00000000.00000000

Host Block Size = 240 - 256 = 16

So IP Address Range :

172.16.0.0
10101100.00010000.00000000.00000000
172.31.255.255
10101100.00011111.11111111.11111111


Is it that you have the second octet of the 172.31.255.255 address converted to binary wrongly? 31 = 00011111 not 11111000

auos

Sorry for mistake, and thank you for explanation.