Private Address

Hello I am confused about private address ranges (for Class C).

Wendel Odom's ICND1 book says the Class C private space is
192.168.0.0 - 192.168.255.0

But I have found quite a bit of other documentation which says it is:
192.168.0.0 - 192.168.255.255

Which would be right?

Thanks in advance!

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Comments

trackit

it would be 192.168.0.0 - 192.168.255.255 sir

dynamik

Those are the same. Odom is just showing you what class C networks are available. In the fourth octet, 0-255 would be hosts for the last network, which is 192.168.255.0.

trackit

dynamik wrote: »

Those are the same. Odom is just showing you what class C networks are available. In the fourth octet, 0-255 would be hosts for the last network, which is 192.168.255.0.

still, address space is through 192.168.255.255 not 192.168.255.0 I dont know of course how Odom book actually phrased it, but they way topic starter did it i would say 192.168.255.255 is correct. He didnt ask what class C private networks are availible.

dynamik

I'm not denying that. I was just explaining why there was confusion. They're saying the same thing.

trackit

yeah, i guess odom actually phrased it little differently (talking about networks not address space) than he posted here...

Mark Knutson

trackit wrote: »

still, address space is through 192.168.255.255 not 192.168.255.0 I dont know of course how Odom book actually phrased it, but they way topic starter did it i would say 192.168.255.255 is correct. He didnt ask what class C private networks are availible.

The network definition doesn't include the host addresses, but they are implied. So on class c, a network with the last octet of 0 will have host 0 representing the network address and 255 as the broadcast address with valid hosts inbetween. As has been stated, its two different ways of describing the same thing.

billscott92787

Dynamik is right. It makes sense because what they are saying Class C (network) the first three octects are what determines the network. The last octect is the host portion so what the other author is saying is for a network choice you have

192.168.0 - 192.168.255 and then the host portion would be 0 - 255

which would equate to 192.168.0.0 - 192.168.255.255