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samritz wrote: » after reading these methods i thought there were pretty cool. check it out and see if maybe i got something wrong somewhere. In class B, XYZ Corporation is using 172.16.0.0 for their networking needs. Each subnet requires 280 IP addresses including the router interface. What subnet mask should be used? Where the numebr of addresses is greater than 256, divide the number of addresses by 256, in this case 280/256 =1 remainder something(forget the rmainder).If there is a remander, add one to the quotient, that is 1 in this case, we have 2. As we did b4 subtract 2 frm 256 and u get 254. that in in the 3rd octect. so the mask is 255.255.254. simple huh?
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