I'm stuck...

jblavenjblaven Member Posts: 16 ■□□□□□□□□□
Question:
What is the maximum number of hosts in a /19 subnet?

Answer Given:
8190 is the total number of hosts (2^14 - 2)

I would have thought since /19 gives you:

11111111111111111110000000000000

...which gives me 13 unmasked bits or zeros. So I thought from the books I am reading that the formula would give me (2^13 - 2). What am I missing? icon_confused.gif:

Thanks,

Joe

Comments

  • gramacorpgramacorp Member Member Posts: 39 ■■■□□□□□□□
    2^1=2
    2^2=4
    2^3=8
    2^4=16
    2^5=32
    2^6=64
    2^7=128
    2^8=256
    2^9=512
    2^10=1024
    2^11=2048
    2^12=4096
    2^13=8192

    Your formula is correct. Seems as though your book made a typo here: (2^14-2)
    should be (2^13-2) Hope that helps.
  • jblavenjblaven Member Posts: 16 ■□□□□□□□□□
    gramacorp wrote: »
    2^1=2
    2^2=4
    2^3=8
    2^4=16
    2^5=32
    2^6=64
    2^7=128
    2^8=256
    2^9=512
    2^10=1024
    2^11=2048
    2^12=4096
    2^13=8192

    Your formula is correct. Seems as though your book made a typo here: (2^14-2)
    should be (2^13-2) Hope that helps.

    Ah, I think you are right. It does make it tough when the book has a slip up! icon_wink.gif It is problem number 7, end of the chapter review on subnetting. Mike Meyers, Network+, All-In-One, Fourth Edition. I guess my confidence is still lacking, because I didn't take it far enough to test what I thought to be right. icon_rolleyes.gif Thanks for your help! icon_thumright.gif
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