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Passed CompTIA Security+ SY0-301
sameerjan77
Member Posts: 10 ■□□□□□□□□□
in Security+
Passed Security + with 894.
1. Want information and pure information read (helps little in EXAM)-
CompTIA Security+™ EXAM GUIDE (Exam SY0 - 301) third editionWm. Arthur Conklin, Gregory White, Dwayne Williams, Roger Davis, Chuck Cothren.
2. Concise information -
CompTIA® Security+™ SY0-301 Exam Cram, Third Edition
Diane Barrett, Kalani K. Hausman, and Martin Weiss
3. Practice tests do plenty.
4. Google all topics and read as much.
1. Want information and pure information read (helps little in EXAM)-
CompTIA Security+™ EXAM GUIDE (Exam SY0 - 301) third editionWm. Arthur Conklin, Gregory White, Dwayne Williams, Roger Davis, Chuck Cothren.
2. Concise information -
CompTIA® Security+™ SY0-301 Exam Cram, Third Edition
Diane Barrett, Kalani K. Hausman, and Martin Weiss
3. Practice tests do plenty.
4. Google all topics and read as much.
Comments
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Nytrocide
Member Posts: 225
Congrats! I hope to take and pass it soon too!
Goals for 2014: CCNA: Voice / CCNA: Security -
OptionsFrankTh
Member Posts: 30 ■□□□□□□□□□
Congratulations.
Almost a perfect score you had.
Are you planning to get more certification in the future?
FrankTh -
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quinnyfly
Member Posts: 243 ■■■□□□□□□□
WOW, that's not far from perfect, perhaps the best score I have ever seen, well done and congrats.The Wings of Technology -
Optionssameerjan77
Member Posts: 10 ■□□□□□□□□□
@ FrankTH
CISSP - all the way now...have to have it at ANY cost. -
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Dakinggamer87
Member Posts: 4,016 ■■■■■■■■□□
Congrats on pass!!
*Associate's of Applied Sciences degree in Information Technology-Network Systems Administration
*Bachelor's of Science: Information Technology - Security, Master's of Science: Information Technology - Management
Matthew 6:33 - "Seek the Kingdom of God above all else, and live righteously, and he will give you everything you need."
Certs/Business Licenses In Progress: AWS Solutions Architect, Series 6, Series 63 -
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whatthehell
Member Posts: 920
Congratz on the pass bhayaa. 2017 Goals:
[ ] Security + [ ] 74-409 [ ] CEH
Future Goals:
TBD -
Optionssameerjan77
Member Posts: 10 ■□□□□□□□□□
@FrankTh
thanks. Now going for Baap of all - CISSPCongratulations.
Almost a perfect score you had.
Are you planning to get more certification in the future?
FrankTh -
Optionsqwertyu1234567
Registered Users Posts: 1 ■□□□□□□□□□
Hi everyone,
There is a question on Security+ SY0-301:Which of the following IP address would be hosts on the same subnet given the subnet mask 255.255.255.224? (Select Two)
A. 10.4.4.125
B. 10.4.4.158
C. 10.4.4.165
D 10.4.4.189
E. 10.4.4.199
How do I find the right answer?
Thank you. -
Optionsabramsgunner
Member Posts: 31 ■■■□□□□□□□
Let's see if I can do this.....
For that subnet mask you convert the last octet to binary.. 11100000 (using Windows built-in calculator)
Note the bits that aren't zero (111)00000 those show you which bits are the 'network mask' bits
Convert the last octet for each IP address
.125 = 1111101 <- calculator doesn't display leading zero, so add enough to show 8 bits = 01111101
.158 = 10011110
.165 = 10100101
.189 = 10111101
.199 = 11000111
Mask of (111)00000 tells us we need to look at first three bits......
.165 and .189 have identicle first three bits, so they should be on the same subnet.
At least that's the way I think it works... LOL
PS.. Best to post a question in it's own thread, makes it easier to find later. -
Optionsmovingzachb
Member Posts: 30 ■■□□□□□□□□
abramsgunner wrote: »Let's see if I can do this.....
For that subnet mask you convert the last octet to binary.. 11100000 (using Windows built-in calculator)
Note the bits that aren't zero (111)00000 those show you which bits are the 'network mask' bits
Convert the last octet for each IP address
.125 = 1111101 <- calculator doesn't display leading zero, so add enough to show 8 bits = 01111101
.158 = 10011110
.165 = 10100101
.189 = 10111101
.199 = 11000111
Mask of (111)00000 tells us we need to look at first three bits......
.165 and .189 have identicle first three bits, so they should be on the same subnet.
At least that's the way I think it works... LOL
PS.. Best to post a question in it's own thread, makes it easier to find later.
Thanks abram
Can anyone second to confirm this is correct?Security+ -
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Darril
Member Posts: 1,588
Yes, that's a good explanation abramsgunner. -
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danny069
Member Posts: 1,025 ■■■■□□□□□□
Congrats on the pass! and abramsgunner you should teach subnetting 101 lolI am a Jack of all trades, Master of None -
Optionsabramsgunner
Member Posts: 31 ■■■□□□□□□□
Nah.. not my work man; I read how to do it last week some time, so it was fresh on my mind....
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SharkDiver
Member Posts: 844
Congratulations on the pass!
Very nice score.
Nice method for finding the answer, abramsgunner.
Just to offer another way,
I do it like this:
I know the following:
.0 is one group of 255
.128 is two groups of 128
.192 is four groups of 64
and
.224 is eight groups of 32
32 is the key
So, I can figure out:
0 - 31 is a subnet
32 - 63 is a subnet
64 - 95 is a subnet
96 - 127 is a subnet
128 - 159 is a subnet
160 - 191 is a subnet
192 - 223 is a subnet
and
224 - 255 is a subnet
From there I look to see where all of the IP Addresses they gave fall.
.125 - falls between 96 and 127
.158 - falls between 128 and 159
.165 - falls between 160 and 191
.189 - falls between 160 and 191
.199 - falls between 192 and 223
So, .165 and .189 are in the same subnet.
