Passed CompTIA Security+ SY0-301

sameerjan77sameerjan77 Member Posts: 10 ■□□□□□□□□□
in Security+
Passed Security + with 894.

1. Want information and pure information read (helps little in EXAM)-

CompTIA Security+™ EXAM GUIDE (Exam SY0 - 301) third editionWm. Arthur Conklin, Gregory White, Dwayne Williams, Roger Davis, Chuck Cothren.

2. Concise information -

CompTIA® Security+™ SY0-301 Exam Cram, Third Edition
Diane Barrett, Kalani K. Hausman, and Martin Weiss

3. Practice tests do plenty.

4. Google all topics and read as much.
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Comments

  • HLRSHLRS Banned Posts: 142
    congrats, I am lookin to knock out sec + also.
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  • NytrocideNytrocide Member Posts: 225
    Congrats! I hope to take and pass it soon too! :)
    Goals for 2014: CCNA: Voice / CCNA: Security
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  • FrankThFrankTh Member Posts: 30 ■□□□□□□□□□
    Congratulations.
    Almost a perfect score you had.
    Are you planning to get more certification in the future?

    FrankTh
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  • quinnyflyquinnyfly Member Posts: 243 ■■■□□□□□□□
    WOW, that's not far from perfect, perhaps the best score I have ever seen, well done and congrats.
    The Wings of Technology
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  • sameerjan77sameerjan77 Member Posts: 10 ■□□□□□□□□□
    @ FrankTH
    CISSP - all the way now...have to have it at ANY cost.
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  • Dakinggamer87Dakinggamer87 Member Posts: 4,016 ■■■■■■■■□□
    Congrats on pass!! icon_thumright.gif
    *Associate's of Applied Sciences degree in Information Technology-Network Systems Administration
    *Bachelor's of Science: Information Technology - Security, Master's of Science: Information Technology - Management
    Matthew 6:33 - "Seek the Kingdom of God above all else, and live righteously, and he will give you everything you need."
    Certs/Business Licenses In Progress: AWS Solutions Architect, Series 6, Series 63
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  • whatthehellwhatthehell Member Posts: 920
    Congratz on the pass bhayaa. :)
    2017 Goals:
    [ ] Security + [ ] 74-409 [ ] CEH
    Future Goals:
    TBD
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  • sameerjan77sameerjan77 Member Posts: 10 ■□□□□□□□□□
    @FrankTh

    thanks. Now going for Baap of all - CISSP
    FrankTh wrote: »
    Congratulations.
    Almost a perfect score you had.
    Are you planning to get more certification in the future?

    FrankTh
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  • _Marauder_Marauder Member Posts: 132 ■■□□□□□□□□
    congratsicon_cheers.gif
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  • qwertyu1234567qwertyu1234567 Registered Users Posts: 1 ■□□□□□□□□□
    Hi everyone,
    There is a question on Security+ SY0-301:
    Which of the following IP address would be hosts on the same subnet given the subnet mask 255.255.255.224? (Select Two)
    A. 10.4.4.125
    B. 10.4.4.158
    C. 10.4.4.165
    D 10.4.4.189
    E. 10.4.4.199
    How do I find the right answer?
    Thank you.
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  • abramsgunnerabramsgunner Member Posts: 31 ■■■□□□□□□□
    Let's see if I can do this.....



    For that subnet mask you convert the last octet to binary.. 11100000 (using Windows built-in calculator)

    Note the bits that aren't zero (111)00000 those show you which bits are the 'network mask' bits


    Convert the last octet for each IP address

    .125 = 1111101 <- calculator doesn't display leading zero, so add enough to show 8 bits = 01111101
    .158 = 10011110
    .165 = 10100101
    .189 = 10111101
    .199 = 11000111


    Mask of (111)00000 tells us we need to look at first three bits......

    .165 and .189 have identicle first three bits, so they should be on the same subnet.


    At least that's the way I think it works... LOL


    PS.. Best to post a question in it's own thread, makes it easier to find later.
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  • movingzachbmovingzachb Member Posts: 30 ■■□□□□□□□□
    abramsgunner wrote: »
    Let's see if I can do this.....


    For that subnet mask you convert the last octet to binary.. 11100000 (using Windows built-in calculator)

    Note the bits that aren't zero (111)00000 those show you which bits are the 'network mask' bits


    Convert the last octet for each IP address

    .125 = 1111101 <- calculator doesn't display leading zero, so add enough to show 8 bits = 01111101
    .158 = 10011110
    .165 = 10100101
    .189 = 10111101
    .199 = 11000111


    Mask of (111)00000 tells us we need to look at first three bits......

    .165 and .189 have identicle first three bits, so they should be on the same subnet.


    At least that's the way I think it works... LOL


    PS.. Best to post a question in it's own thread, makes it easier to find later.

    Thanks abram

    Can anyone second to confirm this is correct?
    Security+
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  • DarrilDarril Member Posts: 1,588
    Yes, that's a good explanation abramsgunner.
    Darril Gibson
    CompTIA A+, Network+, Security+ Blogs
    Daily Network+ and Security+ Test Taking Tips on Twitter
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  • danny069danny069 Member Posts: 1,025 ■■■■□□□□□□
    Congrats on the pass! and abramsgunner you should teach subnetting 101 lol
    I am a Jack of all trades, Master of None
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  • abramsgunnerabramsgunner Member Posts: 31 ■■■□□□□□□□
    Nah.. not my work man; I read how to do it last week some time, so it was fresh on my mind.... icon_wink.gif
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  • SharkDiverSharkDiver Member Posts: 844
    Congratulations on the pass!
    Very nice score.

    Nice method for finding the answer, abramsgunner.

    Just to offer another way,
    I do it like this:

    I know the following:
    .0 is one group of 255
    .128 is two groups of 128
    .192 is four groups of 64
    and
    .224 is eight groups of 32

    32 is the key

    So, I can figure out:
    0 - 31 is a subnet
    32 - 63 is a subnet
    64 - 95 is a subnet
    96 - 127 is a subnet
    128 - 159 is a subnet
    160 - 191 is a subnet
    192 - 223 is a subnet
    and
    224 - 255 is a subnet

    From there I look to see where all of the IP Addresses they gave fall.
    .125 - falls between 96 and 127
    .158 - falls between 128 and 159
    .165 - falls between 160 and 191
    .189 - falls between 160 and 191
    .199 - falls between 192 and 223

    So, .165 and .189 are in the same subnet.
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