I browsed Todd Lammle "CCNA Cisco Certified Network Associate STUDY GUIDE" sixth edition and there was an explanation
how two Windows machines in the same broadcast domain communicate. As you can see, on the second page, there is
"Before the name is resolved, the first thing Bob has to do is broadcast on the LAN to get Sally's MAC address so he can communicate to her PC and resolve her name to an IP address". Shouldn't this be the other way around? I mean
Bob sends out NBNS name query to IP 192.168.0.255(dst MAC is FF:FF:FF:FF:FF:FF) and does not need
Sally MAC address. However,
Sally needs
Bob MAC address.
Sally gets
Bob MAC address by sending ARP request to FF:FF:FF:FF:FF:FF and
Bob replies that 192.168.0.2 is at 00:14:22:be:18:3b. This allows
Sally to send NBNS name query response(which is a unicast message) directly to
Bob. Long story short,
Sally(192.168.0.3) should be the one who sends out the ARP request!
In my opinion this should work like this:
CloudShark I executed "ping -c1 potato" on 192.168.1.68 host.
Did I misunderstand something? Or is there indeed a mistake in the book?
