Ip Subnetting Question...

which of the following address can be assigned to a host when using a subnet mask off 255.255.254.0

A : 175.33.3.255
B : 26.35.3.255
C : 113.10.4.0
D : 186.54.3.0
E : 152.135.7.0
F : 17.35.36.0

Anyone noe the answer?

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Comments

EdTheLad

None of them,with that mask your subnets are 0,2,4,6,8 ....254
A,B are broadcast addresses in subnet 2, C,F are subnets
Answer D,E

A quick edit was called for!

lAwBoY

ed_the_lad wrote:

None of them,with that mask your subnets are 0,2,4,6,8 ....254
A,B are broadcast addresses in subnet 2,
C,D,E,F have a 0 as the host identifier which isnt allowed.

Ermm ... dont think so ...

Undertow

None

EdTheLad

Actually now that i look again, D,E

ziggy

YUP,

Looks like D and E

evanderburg

255.255.254.0

A : 175.33.3.255
B : 26.35.3.255
C : 113.10.4.0
D : 186.54.3.0
E : 152.135.7.0
F : 17.35.36.0

I agree. Just to help out those who are struggling and to prove it, here is why. We already agreed that A & B are broadcasts. C & F are network addresses. Here is my logic.

NOTE: 255 octets are eliminated in my logic for simplicity because they are insignificant.

C:
Address: 00000100.00000000
Subnet: 11111110.00000000
Binary AND 00000100.00000000
The address and the binary AND come to the same result so this address is the same as it's network address. C is invalid

Address: 00000011.00000000
Subnet: 11111110.00000000

Binary AND 00000010.00000000
The address and Binary AND differ so this address is ok.

E:
Address: 00000111.00000000
Subnet: 11111110.00000000
Binary AND 00000110.00000000
The address and Binary AND differ so this address is ok.

F:
Address: 00100010.00000000
Subnet: 11111110.00000000
Binary AND 00100010.00000000
The address and the binary AND come to the same result so this address is the same as it's network address. F is invalid