Ip Subnetting Question...

which of the following address can be assigned to a host when using a subnet mask off 255.255.254.0

A : 175.33.3.255
B : 26.35.3.255
C : 113.10.4.0
D : 186.54.3.0
E : 152.135.7.0
F : 17.35.36.0

Anyone noe the answer?

Find more posts tagged with

SAVE $250 on Your CISCO Boot Camp — Use Code "EXAM26"

Exclusively for TechExams members for Infosec Boot Camps starting before April 30, 2026

View CISCO Boot Camps

Comments

EdTheLad

None of them,with that mask your subnets are 0,2,4,6,8 ....254
A,B are broadcast addresses in subnet 2, C,F are subnets
Answer D,E

A quick edit was called for!

lAwBoY

ed_the_lad wrote:

None of them,with that mask your subnets are 0,2,4,6,8 ....254
A,B are broadcast addresses in subnet 2,
C,D,E,F have a 0 as the host identifier which isnt allowed.

Ermm ... dont think so ...

Undertow

None

EdTheLad

Actually now that i look again, D,E

ziggy

YUP,

Looks like D and E

evanderburg

255.255.254.0

A : 175.33.3.255
B : 26.35.3.255
C : 113.10.4.0
D : 186.54.3.0
E : 152.135.7.0
F : 17.35.36.0

I agree. Just to help out those who are struggling and to prove it, here is why. We already agreed that A & B are broadcasts. C & F are network addresses. Here is my logic.

NOTE: 255 octets are eliminated in my logic for simplicity because they are insignificant.

C:
Address: 00000100.00000000
Subnet: 11111110.00000000
Binary AND 00000100.00000000
The address and the binary AND come to the same result so this address is the same as it's network address. C is invalid

Address: 00000011.00000000
Subnet: 11111110.00000000

Binary AND 00000010.00000000
The address and Binary AND differ so this address is ok.

E:
Address: 00000111.00000000
Subnet: 11111110.00000000
Binary AND 00000110.00000000
The address and Binary AND differ so this address is ok.

F:
Address: 00100010.00000000
Subnet: 11111110.00000000
Binary AND 00100010.00000000
The address and the binary AND come to the same result so this address is the same as it's network address. F is invalid