Subnetting Class B Question

Hey Guys,

i came across this question on subnettingquestions.com - Free Subnetting Questions and Answers Randomly Generated Online

What is the subnet addesss of 172.16.159.159/22?

Now from working out the subnet mask i understand the increment is going to be 4.

172.16.0.0
172.16.0.4
E.C.T.

However seeing as my maths isn't the best and i will hardly have time on my side in the exam to go through all those hundreds of numbers. Could you help me on how i would get not only the answer but even close to those numbers.

Note: The answer should be 172.16.156.0

I really appreciate any help you could provide as i really want to crack class b subnetting.

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Comments

FloOz

It would actually increment in the 3rd octet not the 4th.

So
172.16.0.0
172.16.4.0
.
.
.
172.16.156.0 - 172.16.159.255
172.16.160.0

In this situation I was able to figure it out quickly because I knew 156 is divisible by 4

RouteMyPacket

We are working with the following

172.16.156.0 - 172.16.159.255

22 bits were used right?

11111111.11111111.11111100.00000000

So from that we know we will be working with the 3rd octet, that is where the changes will take place.

The question is simple as it is only asking you the "subnet" address.

The subnet is 255.255.252.0

The network address is 172.16.156.0 and the broadcast is 172.16.159.255