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Netstudent wrote: Well thats a new one... Lets see.../20 = 255.255.240.0 0, 16 ..........144, 160 range is 172.60.144.1 - 172.60.159.254 on the 10th subnet 500th host.... 500 - 255 = 245 172.60.144.1 - 172.60.144.255 would be the first 255 hosts So i think it would be 172.60.145.245 Thats a wierd one...
Netstudent wrote: well it's all in the binary...But binary calculations are too slow and once you understand the binary side, you can begin to use shortcuts. In the real world your gonna have to use shortcuts because you can't sit there and write out binary code everytime you want to come up with a solution. That said....here my logic 255.255.240.0 I look at the Octet in question wich is the 3rd octet. I take that nunber and subtarct it from 256. 256 - 240 = 16 Therefore your subnets will increment by 16. First subnet is 0 then 16 then 32 then 48 then 64 keep doing that untill you get to the 10th subnet. If you want to do it real quick and in a hurry, 10 x 16 = 160 right. Well you have to count 0 as the first subnet, so whats 160 - 16? 144 so the 10th subnet is 172.60.144.0 and the next subnet would be 172.60.160.0. Now you have to find whats in between. 172.60.144.1 - 172.60.159.254 The next address is braodcast which is 172.60.159.255 Then the next IP is the next subnet 172.60.160.0
stevcha wrote: Netstudent wrote: well it's all in the binary...But binary calculations are too slow and once you understand the binary side, you can begin to use shortcuts. In the real world your gonna have to use shortcuts because you can't sit there and write out binary code everytime you want to come up with a solution. That said....here my logic 255.255.240.0 I look at the Octet in question wich is the 3rd octet. I take that nunber and subtarct it from 256. 256 - 240 = 16 Therefore your subnets will increment by 16. First subnet is 0 then 16 then 32 then 48 then 64 keep doing that untill you get to the 10th subnet. If you want to do it real quick and in a hurry, 10 x 16 = 160 right. Well you have to count 0 as the first subnet, so whats 160 - 16? 144 so the 10th subnet is 172.60.144.0 and the next subnet would be 172.60.160.0. Now you have to find whats in between. 172.60.144.1 - 172.60.159.254 The next address is braodcast which is 172.60.159.255 Then the next IP is the next subnet 172.60.160.0 Your method seems pretty clear cut. So just another question will you always be able to find the number of subnets, hosts, and range of ips using this method? I haven't gone wrong yet....I just want to reiterate the importance of knowing the binary methods first. If you knew the binary method, you would see the underlying binary logic in my examples. Any CCNA'er should have Todd Lammle's 5th edition sybex, if not for anything but his subnetting tutorial. He gives you the binary method, but also the same shortcuts and ways of thinking about it as I do. One thing I have learned from studying for NP though, is that when you are designing an IP infrastructure for a really big enterprise that must flow and be hierarchical, the binary method is actually easier than trying to crunch all the numbers.
Netstudent wrote: well it's all in the binary...But binary calculations are too slow and once you understand the binary side, you can begin to use shortcuts. In the real world your gonna have to use shortcuts because you can't sit there and write out binary code everytime you want to come up with a solution. That said....here my logic 255.255.240.0 I look at the Octet in question wich is the 3rd octet. I take that nunber and subtarct it from 256. 256 - 240 = 16 Therefore your subnets will increment by 16. First subnet is 0 then 16 then 32 then 48 then 64 keep doing that untill you get to the 10th subnet. If you want to do it real quick and in a hurry, 10 x 16 = 160 right. Well you have to count 0 as the first subnet, so whats 160 - 16? 144 so the 10th subnet is 172.60.144.0 and the next subnet would be 172.60.160.0. Now you have to find whats in between. 172.60.144.1 - 172.60.159.254 The next address is braodcast which is 172.60.159.255 Then the next IP is the next subnet 172.60.160.0 Your method seems pretty clear cut. So just another question will you always be able to find the number of subnets, hosts, and range of ips using this method?
hodgey87 wrote: hi guys, im can pretty much do subnetting now but is there a quick way in which i can find a certain host on a certain subnet for example find the 500th host on the 10th subnet 172.60.10.0/20 any help would be appreciated thanks
motherwolf wrote: 0 is not a host, it's a network address. IP Subnet Zero allows you to use 0 as network address. I believe Netstudent is correct.
motherwolf wrote: 172.60.145.0 can be used as a host address? Sure b'out that? Anyone else want to jump in here and clarify this?
NeonNoodle wrote: Netstudent's answer is almost correct, but his method is sound. It should be 244, not 245. I think he might not have considered 0 when counting. I think the other answer would be correct if you're enforcing the no ip subnet-zero rule.
Netstudent wrote: NeonNoodle wrote: Netstudent's answer is almost correct, but his method is sound. It should be 244, not 245. I think he might not have considered 0 when counting. I think the other answer would be correct if you're enforcing the no ip subnet-zero rule. DOW!!!! [slaps head]I was thinking about that and the 0 in the last octect got me confused. I'm gonna chalk that one off as one wierd problem. Ya wolf it can...I really contemplated that for a while when I was explainig the answer but just didn;t take it into consideration.
tube wrote: Hello NetStudent I am pretty sure that the subnet address at 10th is 172.60.160.0 and the host 500th is 172.60.161.244 I also double check with a Subnet calculator, please see the link
tube wrote: The picture I posted shows a 2^4 = 16 subnets, but only 14 usable subnets. So I excluded the first and the last one. When the command ip subnet-zero is configured, then all zeros subnet are allowed. It will be a different story.
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