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Summarizing without over-summarization

r_durantr_durant Member Posts: 486 ■■■□□□□□□□
I'm sure some will say this is a CCNA question... icon_redface.gif Bear with me, just seeking clarification...

But, i'm going over the CCNP BSCI Official Exam Cert Guide 4th Ed. In ch2 Q&A, it asks...

Summarize the following without over-summarizing:
- 192.168.160.0/24
- 192.168.162.0/23
- 192.168.161.0/24
- 192.168.164.0/22

It gives the ans in the appendix as 192.168.160.0/21. While this summarizes all the addresses, I'm sure it over-summarizes with 165.0, 166.0 & 167.0 included in the summary address.
CCNA (Expired...), MCSE, CWNA, BSc Computer Science
Working on renewing CCNA!

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    aquillaaquilla Member Posts: 148 ■■■□□□□□□□
    That's correct.

    192.168.160.0/24 = 192.168.160.0 - 192.168.160.255
    192.168.161.0/24 = 192.168.161.0 - 192.168.161.255
    192.168.162.0/23 = 192.168.162.0 - 192.168.163.255
    192.168.164.0/22 = 192.168.164.0 - 192.168.167.255

    Therefore the summary address of 192.168.160.0/21 is right.

    S.
    Regards,

    CCNA R&S; CCNP R&S
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    mkomonmkomon Member Posts: 37 ■■□□□□□□□□
    Hi,

    165.0, 166.0 & 167.0 are all covered by the 192.168.164.0/22 subnet. 192.168.160.0/21 makes no over-summarization.

    HTH,

    Martin
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    r_durantr_durant Member Posts: 486 ■■■□□□□□□□
    aquilla wrote: »
    That's correct.

    192.168.160.0/24 = 192.168.160.0 - 192.168.160.255
    192.168.161.0/24 = 192.168.161.0 - 192.168.161.255
    192.168.162.0/23 = 192.168.162.0 - 192.168.163.255
    192.168.164.0/22 = 192.168.164.0 - 192.168.167.255

    Therefore the summary address of 192.168.160.0/21 is right.

    S.

    I feel like a dope icon_redface.gif...I didn't expand "192.168.164.0/22 = 192.168.164.0 - 192.168.167.255"

    Thanks...
    CCNA (Expired...), MCSE, CWNA, BSc Computer Science
    Working on renewing CCNA!
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