Help with VLSM and Route summariztion with and without contigious networks.

Tommy2727Tommy2727 Member Posts: 48 ■■□□□□□□□□
Greeting all, I'm back and I'm very upset once again. For some reason I can not grasp the concept and fundamentals of route summarization & VLSM. I'm pretty comfortable with the basic fundamentals but implementing and finding a discontigious summary route and when to use VLSM to find specific networks / hosts has me stumped.. Can some one please dummy down the formula, process or post some resources why and how? these q & a's came from Boson but I can not see how and why . Please..... any assistance is greatly appreciated.

Cheers!

1. What is the most efficient summarization that can be used to advertise for the following networks?

172.1.4.0/25

172.1.4.128/25

172.1.5.0/24

172.1.6.0/24

172.1.7.0/24

Answer 172.1.4.0/22

Can someone please dummy down this?

2. A summarized route for a router is 192.1.144.0/20 which of the following packet destinations addresses will be forwarded?

answer?
192.1.151.254
192.1.59.2


Can someone tell me why please? my formula is flailed
Practice, Practice, and more Practice make Perfection.....

Comments

  • BrizoHBrizoH Member Posts: 73 ■■■□□□□□□□
    Bit of a rushed reply below, apologies if anything isn't too clear.

    1. What is the most efficient summarization that can be used to advertise for the following networks?

    172.1.4.0/25

    172.1.4.128/25

    172.1.5.0/24

    172.1.6.0/24

    172.1.7.0/24

    Answer 172.1.4.0/22

    Can someone please dummy down this?


    A /22 subnet mask is 255.255.252.0 - giving you an increment of 4 in the 3rd octet, which means valid networks would include:

    172.1.0.0 - 172.1.3.255
    172.1.4.0 - 172.1.7.255*
    172.1.8.0 - 172.1.11.255
    etc


    The second network includes all of your more specific subnets in need of summarisation so it's a perfect summary route.

    2. A summarized route for a router is 192.1.144.0/20 which of the following packet destinations addresses will be forwarded?

    answer?
    192.1.151.254
    192.1.59.2

    Can someone tell me why please? my formula is flailed

    Again, once you have your increment it's easier.

    A /20 subnet is 255.255.240.0 which gives you an increment of 16 in the 3rd octet, so your valid subnets would be:

    192.1.0.0 - 192.1.15.255
    192.1.16.0 - 192.1.31.255
    192.1.32.0 - 192.1.47.255
    ..
    ..
    192.1.128.0 - 192.1.143.255
    192.1.144.0 - 192.1.159.255 *
    192.1.160.0 - 192.1.175.255


    Of the two possible answers only 192.1.151.254 belongs to the given subnet.

    I'm a fan of Jeremy Ciora's subnetting method - it's all about getting your increment.

    https://learningnetwork.cisco.com/servlet/JiveServlet/previewBody/6014-102-1-19236/Subnetting%20Examples.pdf

    Once I had this nailed (with lot's of practise on http://www.subnettingquestions.com) it really helped in the exam.
  • Tommy2727Tommy2727 Member Posts: 48 ■■□□□□□□□□
    BrizoH wrote: »
    Bit of a rushed reply below, apologies if anything isn't too clear.




    A /22 subnet mask is 255.255.252.0 - giving you an increment of 4 in the 3rd octet, which means valid networks would include:

    172.1.0.0 - 172.1.3.255
    172.1.4.0 - 172.1.7.255*
    172.1.8.0 - 172.1.11.255
    etc


    The second network includes all of your more specific subnets in need of summarisation so it's a perfect summary route.



    Again, once you have your increment it's easier.

    A /20 subnet is 255.255.240.0 which gives you an increment of 16 in the 3rd octet, so your valid subnets would be:

    192.1.0.0 - 192.1.15.255
    192.1.16.0 - 192.1.31.255
    192.1.32.0 - 192.1.47.255
    ..
    ..
    192.1.128.0 - 192.1.143.255
    192.1.144.0 - 192.1.159.255 *
    192.1.160.0 - 192.1.175.255


    Of the two possible answers only 192.1.151.254 belongs to the given subnet.

    I'm a fan of Jeremy Ciora's subnetting method - it's all about getting your increment.

    https://learningnetwork.cisco.com/servlet/JiveServlet/previewBody/6014-102-1-19236/Subnetting%20Examples.pdf

    Once I had this nailed (with lot's of practise on subnettingquestions.com - Free Subnetting Questions and Answers Randomly Generated Online) it really helped in the exam.


    Ok why increments of 4, for /22 252 mask and why increment of 16 for /20 subnet 255.255.240.0.. This does not not make sense to me. I was told to use block sizes.. ugh...I'm very comfortable with subnetting but i so confusedicon_sad.gif ...
    Practice, Practice, and more Practice make Perfection.....
  • Tommy2727Tommy2727 Member Posts: 48 ■■□□□□□□□□
    Tommy2727 wrote: »
    Ok why increments of 4, for /22 252 mask and why increment of 16 for /20 subnet 255.255.240.0.. This does not not make sense to me. I was told to use block sizes.. ugh...I'm very comfortable with subnetting but i so confusedicon_sad.gif ...




    ahhhhh! I just read over this pdf and wow, I see the light again. the increment is the most least significant bit on the default mask written in binary, after that, you count up by that increment and see which network encompass untill you reach your new custom mask.

    Ahh I think Im ok until later icon_sad.gif. are there any q and a's like on subnettingquestions.com
    Practice, Practice, and more Practice make Perfection.....
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