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I'm stuck...
Question:
What is the maximum number of hosts in a /19 subnet?
Answer Given:
8190 is the total number of hosts (2^14 - 2)
I would have thought since /19 gives you:
11111111111111111110000000000000
...which gives me 13 unmasked bits or zeros. So I thought from the books I am reading that the formula would give me (2^13 - 2). What am I missing?
:
Thanks,
Joe
What is the maximum number of hosts in a /19 subnet?
Answer Given:
8190 is the total number of hosts (2^14 - 2)
I would have thought since /19 gives you:
11111111111111111110000000000000
...which gives me 13 unmasked bits or zeros. So I thought from the books I am reading that the formula would give me (2^13 - 2). What am I missing?
:Thanks,
Joe
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gramacorp
Member Posts: 39 ■■■□□□□□□□
2^1=2
2^2=4
2^3=8
2^4=16
2^5=32
2^6=64
2^7=128
2^8=256
2^9=512
2^10=1024
2^11=2048
2^12=4096
2^13=8192
Your formula is correct. Seems as though your book made a typo here: (2^14-2)
should be (2^13-2) Hope that helps. -
Optionsjblaven
Member Posts: 16 ■□□□□□□□□□
2^1=2
2^2=4
2^3=8
2^4=16
2^5=32
2^6=64
2^7=128
2^8=256
2^9=512
2^10=1024
2^11=2048
2^12=4096
2^13=8192
Your formula is correct. Seems as though your book made a typo here: (2^14-2)
should be (2^13-2) Hope that helps.
Ah, I think you are right. It does make it tough when the book has a slip up!
It is problem number 7, end of the chapter review on subnetting. Mike Meyers, Network+, All-In-One, Fourth Edition. I guess my confidence is still lacking, because I didn't take it far enough to test what I thought to be right. 
Thanks for your help! 