Hi, I don't post much, so this is my first post and I'm hoping someone could please explain this answer to me...much appreciated. I don't understand which would be added to the routing table from a debug ip rip command...please help me understand

. This is from the cd in back of the book Pearson IT Cert. Practice test.
Heres the question...The exhibit shows an output from a working RIP router. Which entries are put into the routing table?
EXHIBIT
HICKORY#debug ip rip
RIP protocol debugging is on
HICKORY#
00:35:50: RIP: received v1 update from 207.87.7.2 on Ethernet0
00:35:50: 10.0.0.0 in 2 hops
00:35:50: 207.87.1.96 in 1 hops
00:35:50: 207.87.3.0 in 2 hops
00:35:50: 207.87.4.0 in 2 hops
00:35:50: 207.87.5.0 in 3 hops
00:35:50: 207.87.6.0 in 3 hops
00:35:50: RIP: received v1 update from 207.87.1.33 on Serial0
00:35:50: 10.0.0.0 in 2 hops
00:35:50: 207.87.1.64 in 1 hops
00:35:50: 207.87.3.0 in 2 hops
00:35:50: 207.87.4.0 in 2 hops
00:35:50: 207.87.7.0 in 1 hops
00:35:50: 207.87.5.0 in 3 hops
00:35:50: 207.87.6.0 in 3 hops
00:35:50: RIP: received v1 update from 207.87.1.65 on Serial1
00:35:50: 10.0.0.0 in 1 hops
00:35:50: 207.87.1.32 in 1 hops
00:35:50: 207.87.1.64 in 1 hops
00:35:50: 207.87.3.0 in 2 hops
00:35:50: 207.87.4.0 in 2 hops
00:35:50: 207.87.7.0 in 2 hops
00:35:50: 207.87.5.0 in 3 hops
00:35:50: 207.87.6.0 in 3 hops
HICKORY#
ANSWER CHOICES...
A. 10.0.0.0 in 1 hop <<this is the answer
B. 0.0.0.0/0 in 2 hops
C. 207.87.1.0 in 1 hop
D. 207.87.5.0 in 3 hop <<this is the answer
E. 10.0.0.0 in 2 hops
F. 207.87.1.0 in 2 hops