Ipv6

Comments

• fredrikjj Member Posts: 879

  November 2014

  The simple approach is to subnets based on the hextet boundary. You could just do:
  
  2343:2155:1266:1235:0001::/80
  2343:2155:1266:1235:0002::/80
  2343:2155:1266:1235:0003::/80
  ...
  2343:2155:1266:1235:ffff::/80
  
  That gives you 65,535 subnets (actually, 1 less because I didn't use the 0000 subnet). The problem is that you now have a 48 bit host portion, which doesn't support autoconfiguration. On links that you manually configure, this doesn't matter though. The more common approach is to have a /48 and then use the fourth hextet to subnet.
  
  You might have 2343:2155:1266::/48 and do same thing as above:
  
  2343:2155:1266:0001::/64
  2343:2155:1266:0002::/64
  2343:2155:1266:0003::/64
  
  If you don't want to use an entire hextet for subnetting you need to be more careful, but as long as you don't subnet within one of the "nibbles" (4 bits representing a hex digit) it's pretty easy.

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• sina2011 Member Posts: 239 ■□□□□□□□□□

  November 2014

  thanks for you reply.
  
  so if you fill up the first octect how do you move onto the other one thats something i dont get?
  
  I see in your network ranges you are incrementing by 1 shouldnt you increment the same way in ipv4 if so how do you find the increment im just abit confused with ipv6.
  
  thanks.

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• fredrikjj Member Posts: 879

  November 2014

  I don't understand your questions.

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• networker050184 Mod Posts: 11,962 Mod

  November 2014

  Break it into binary and it's the same thing as IPv4.

  An expert is a man who has made all the mistakes which can be made.

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