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Deathmage wrote: » I used subnetting.net like 7 months ago when I didn't know subnetting as well as I do now. I think I'll revisit it and add that to my daily madness.. Question for the CCNP's... does it get any easier with CCNP or is CCENT/CCNA supposed to be this hard with the Cisco Exams and how they word them? ...or is just a fact of life that I need to get used to their poor wording?
xnx wrote: » CCNP is much more difficult sadly, you've really got to be dedicated to learning the protocols and even reading RFCs when the books need calrification
koz24 wrote: » How would they hold it against you? Dude, just find the answer any way you can. If show run works and it gets you the answer then use it!
thomas_ wrote: » I agree with koz24, my thought process is that if they don't want you to use a "show running-config" on a simlet then you are not going to be able to use that command. If it's available use it, if it's not then work your way around it. As far as subnetting goes, here's how I do it. If it helps you great, if it doesn't then just forget I even wrote it. I don't use a magic number or anything like that. I just remember that when you have a set of 8 bits the left-most bit when turned on has a 128 decimal value, second from the left = 64, third from left =32, fourth from left = 16. The above is important because that value will tell you how much you should increment each subnet by in a particular octet. Let's assume a network had an original /8 address and we are going to subnet it. In a /9 subnet there is only one bit being used in the second octet for subnetting. Since a subnet mask by definition has only consecutive ones starting from the left(11111111.10000000.0.0) that means the subnets will increment by 128 within the second octet, we are doing nothing with the first octet since that originally contained all network bits. The two subnets are x.0.0.0 and x.128.0.0 If you had a /10 ip address the subnet mask would be (11111111.11000000.0.0). In this case two bits are being used in the second octet for subnetting. Looking at their respective decimal values, starting from the left they are 128 and 64 respectively. Based on this I know that the subnets are going to be multiples of 64 starting with 0. The subnets then are x.0.0.0, x.64.0.0, x.128.0.0, x.192.0.0. If we looked at the subnet mask in decimal it would be 255.192.0.0. The magic number tells you to subtract 256-192 = 64. Notice how this is equal to the decimal value of the subnet bit being used that is the farthest to the right in the second octet. If you had a /11 ip address the subnet mask would be (11111111.11100000.x.x). Now there are three bits in the second octet being used for subnetting. Looking at their decimal values from left to right they are 128, 64, and 32. We can conclude that the subnets are going to increments of 32 starting with 0. The subnets are x.0.0.0, x.32.0.0, x.64.0.0, x.96.0.0, x.128.0.0, x.160.0.0, x.192.0.0, x.224.0.0. The decimal subnet mask for above is 255.224.0.0. Using the magic number 256-224 = 32. Again Notice how this number corresponds to the decimal value of the subnet bit that is furthest to the right when it is turned on. If you have a subnetting problem that crosses octet boundaries that is where it gets a little tricky. Lets say that you are using a /9 for subnetting, but the original network only used /7 for the network. This would mean that in the first octet, the far right bit is the only one being used for subnetting. In the second octet the far left bit is the only bit being used for networking.(nnnnnnns.shhhhhhh.hhhhhhhh.hhhhhhhh) where n =network bits, s = subnet bits, h = host bits. For the sake of discussion let's say the original network is 64.0.0.0 /7. The first seven bits are unchanging. Bits 8 and 9 are the bits that gives us our subnets. The new subnets would then be 64.0.0.0 /9(the subnet bit in the first and second octet are both turned off), 64.128.0.0 /9(subnet bit in first octet off, subnet bit in second octet on), 65.0.0.0 /9(subnet bit in first octet is on, second octet is off), and 65.128.0.0(subnet bit in both octets on). If we analyze it we see that the second octet only changed by multiples of 128, but only when the subnet bit was on. The first octets value was only being changed by multiples of 1, but only for the cases when the subnet bit for the first octet was turned on. The broadcast address for the first subnet would be 64.127.255.255(one less than the second subnet id), for the second it would be 64.255.255.255(one less than the third subnet id), for the third it would be 65.127.255.255(one less than the fourth subnet id) and for the fourth it would be 65.255.255.255. Once you know the ranges you just have to figure out which subnet range a given ip address falls within. Once you know which octets you are working within for the subnets it gets pretty easy to find the subnet the ip address is in.
Jon_Cisco wrote: » never looked at their study material I just used the practice test. I found when I rushed for a high score I did a lot worse. Just answer slowly and your speed will increase quickly.
Mooseboost wrote: » You have this for sure man. You are an absolutely inspiration with your dedication.
Skandiluz wrote: » I read every page of this and I love how devoted you are. +1 for you. Good luck or your next attempt and we know you're going to destroy it this time!
Deathmage wrote: thanks bro, been spending about 15 minutes a day at work doing subnetting.net and then 20 minutes to an hour at home (but at home I get carried away and it takes away from books reading) just so I keep my skills sharp. I only use what I will be making on my white board as reference and that is the CIDR chart from /8 to /32 with the custom masks and then the block counts per octet. I'm getting better and better at subnetting with speed and accuracy. I'll be super pissed if IP addresses IPv4 and v6 is not 100% on the next go through...
SpetsRepair wrote: Subnetting video that really helped mehttps://www.youtube.com/watch?v=rs39FWDhzDs
mikeybinec wrote: » So if I tossed you a subnet question could you do it in about 30 seconds? Think fast: What's the block size of a slash 15? (/15 or 255.254.0.0) (hint: the block size of a /15 is the same as a /23)
techfiend wrote: » and 10 to the power of 2 = 1024.
Deathmage wrote: » 2?
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