Help... how do I figure this sub problem.

I got the subnetting basics down but can't put it together to solve this, thank you.

Network ID: 213 214 150 0
Subnets Required: 13

What is the subnet mask?

1st Available Host
Address of Subnet 1?

Max # of hosts/subnet?

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Comments

miller811

The IP scheme that they gave you was a single subnet with 254 hosts possible. It is a Class C address which is a /24 or 255.255.255.0

Class C Range 192 - 223 in the first octet

it could be broken into two segments of 128 bits by changing the mask to a /25 = 126 usable hosts per subnet
it could also be broken into 4 subnets of 64 bits by changing the mask to a /26 mask = 62 usable host/subnet
it could also be broken into 8 subnets of 32 bits with a /27 mask = 30 usable hosts/subnet
it could also be broken into 16 subnets of 16 bits with a /28 mask = 14 usable hosts
it could also be broken into 32 subnets of 8 bits with a /29 mask = 6 usable hosts
it could also be broken into 64 subnets of 4 bits with a /30 mask = 2 usable hosts

That should be enough to get you started....

Haruna Umar Adoga

The given network (213.214.150.0) should be subnetted to meet the requirements of 13 hosts right ?
First you have to know that the above address is a class c address which also means that it has a subnet mask of 255.255.255.0.
Then you can use the block size method of solving the problem (VLSM)
with your powers of 2 block sizes,
i.e 128 64 32 16 8 4 2 1 = 255 (for all ones)

from the above block sizes, its obvious that to meet the requirements of 13 hosts, you will need to use a block size of 16 which means that the first 4 bits will be ON (borrowed or added to your given subnet mask which is /24 in this case)

Therefore, using a block size of 16 gives us a new subnet mask of /28 i.e 255.255.255.240 (adding 4 bits to the given mask of /24) which will meet the above requirements of 13 hosts

since 4 bits were borrowed (added), it implies that :
number of subnets = 2^4 = 16
number of valid hosts/subnet = 2^4 - 2 = 16-2 = 14 hosts per subnet.

your subnets are :
(213.214.150.0 to 213.214.150.150) i.e first subnet

(213.214.150.16 to 213.214.150.31) 2nd subnet

(213.214.150.32 to 213.214.150.47) 3rd subnet

. . . and so on.

which means that the first valid host on the first subnet is :
213.214.150.1 with a broadcast address of 213.214.150.15 and a subnet mask of /28 (255.255.255.0)

and max # of hosts/ subnet = 14.

Hope you get to understand this method.

SurferdudeHB

Thank you all, I will dissect the info and learn.

tech-airman

SurferdudeHB wrote: »

I got the subnetting basics down but can't put it together to solve this, thank you.

Network ID: 213 214 150 0
Subnets Required: 13

What is the subnet mask?

1st Available Host
Address of Subnet 1?

Max # of hosts/subnet?

SurferdudeHB,

What class is the network address?

SurferdudeHB

tech-airman wrote: »

SurferdudeHB,

What class is the network address?

Class C

miller811

did it click for you yet Surferdude?

tech-airman

SurferdudeHB wrote: »

Class C

SurferdudeHB,

What is the default mask for a Class C network?

SurferdudeHB

tech-airman wrote: »

surferdudehb,

what is the default mask for a class c network?

255.255.255.0

SurferdudeHB

miller811 wrote: »

did it click for you yet Surferdude?

Starting to, going to do another problem.

mella060

SurferdudeHB wrote: »

I got the subnetting basics down but can't put it together to solve this, thank you.

Network ID: 213 214 150 0
Subnets Required: 13

What is the subnet mask?

Max # of hosts/subnet?

hmmm lets see...this is a class C address so the default subnet mask is 255.255.255.0

You require 13 subnets right ? So then what power of 2 will give you the required amount of subnets ?

2^3 will only give you 8 subnets...2^4 will give you 16 subnets...so then you require 4 subnet bits.

So your subnet mask would be 255.255.255.240 /28...does that sound alright ?

That leaves you with 4 host bits so 2^4-2 = 14 hosts per subnet

SurferdudeHB

Ok I think I got it guys. I reviewed my CBT Nuggets videos and can now put it all together. Thank you all!

tech-airman

SurferdudeHB wrote: »

255.255.255.0

SurferdudeHB,

If you borrowed 1 subnet bit, how many subnets can you have?
Does it meet the design requirement of "Subnets Required: 13?"

SurferdudeHB

tech-airman wrote: »

SurferdudeHB,

If you borrowed 1 subnet bit, how many subnets can you have?
Does it meet the design requirement of "Subnets Required: 13?"

No you need to borrow 4 bits.