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bcall64 wrote: » That's what I thought. Ok I have until Monday until my ICND1 exam. Now before the exam you have about 10 minutes right in the room with a piece of paper or something? How does that work? Maybe I could write all of them out?
8 7 6 5 4 3 2 1 128 64 32 16 8 4 2 1 128 192 224 240 248 252 254 255 255 127 61 31 15 7 3 1
bcall64 wrote: » Ok I'm solid with subnetting but I'm not under 30 seconds like everyone believes I should be. I get questions where I have to figure out the host range for a subnetwork that is in the 200's or 100's and it takes some time. For instance I need to find what network 192.168.200.141 /28 is on. Well easy enough I know my increment is 16 because my lowest bit is 16. Now I am going to count up 192.168.200.0, 16, 32, 48, etc etc etc. Well that's great and all but if I add these in my head I mistakes and get the question wrong. So I'm rushing through adding these numbers up and I get the answers right but it takes time. Anyone run into this same situation before? Is there a trick to speed this up?
daveccna wrote: » It may well have been on here that I read it but there is a quick way of answering the which subnet is this on question if you have the block size. Simply divide the presented number by the block size and then cut any fraction off of the result. Then multiply your new whole number by the block size to get the network address. Are you allowed a calculator in the exam?
miller811 wrote: » No calculators.... sorry
blackninja wrote: » This is what I do: We are looking for network of 192.168.0.125 /28 = 192.168.0.125 255.255.255.255.240 Remember you don't have to count in 16s you can count muliples of 16. We all know 4 x 16 = 64 then 2 x 64 = 128 128 - 16 = 112 So subnet of 192.168.0.125 /28 = 192.168.0.112 /28 It's that easy
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