Book now with code EOY2025
ch1vas wrote: » I'll explain why I'm confused after I get some answers .
Ltat42a wrote: » Have you tried writing this IP out in binary? That will give you your answer too.
xXErebuS wrote: » No it wont... and it all depends if your talking about classful networks; if you are then jd is correct... see belowClassful network - Wikipedia, the free encyclopedia Please note in real world one may say use the network 10.10.10.0 and if you ask what mask they may say use a class C on it; that simply means its 10.10.10.0/24. As to standard generalization rule for classful routing see wikipedia link.
Ltat42a wrote: » The first octet - 150, written in binary = 10010110. The first 2 bits (10) is in the Class B range.
ch1vas wrote: » Oh I see. Darn, I thought the Classes are defined by the actual IP address and not by the binary number. Thanks for clarifying.
networker050184 wrote: » You are mixing two things together. First you have classful address ranges that are predefined (A, B, C etc). These are what you are looking for in the first octet. Second you are looking at VLSM which allows you to use classless addressing where in you can assign any length mask to any class. In the end the mask length has nothing to do with address class when thinking in the current classless world of addressing.
ch1vas wrote: » 150.150.1.0 indicates that only the last octet is for Hosts
Michael2 wrote: » There's also a class D and class E but those are experimental.
Use code EOY2025 to receive $250 off your 2025 certification boot camp!