Can you subnet this

Hello peeps,

Once again I would like to ask your help regarding subnetting.
I'm confuse with the 192.168.10.0/24
can you use this as an ip and what class is it A, B or C?

Thanks ,
chinaman

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Comments

chinaman

In class c I know that it's upto 25 - 30
128 - 25
192 - 26
to
252 / 30

This is for class c

but in class b is /17 to /24

kplab

192.168.10.0/24 is a Class C network. You can subnet it using a subnet mask of /25 to /30.

A Class B network has the default netmask of /16. You can subnet a Class B network using a subnet mask of /17 to /30.

You can find more information about IP addressing and subnetting in the following webpages:

http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a00800a67f5.shtml#ustand_subnet
http://www.learntosubnet.com/

mikeyoung

as displayed in your question it is a network address with a subnet mask of 255.255.255.0 so, you can NOT use it as an ip node address.

It is officically a class "C" network address.

chinaman

Can you tell me why I cannot use it? and maybe I'm just confuse with this /24.

Ching

chinaman

I see it's bec 192.168.10.0/24 and cannot be use because of the rule that the minimum bits is 2 bits.

It belongs to class C... and is in the private addresses ranges

It the class C range, the lowest IP address is 192.0.0.0 and the highest is 223.255.255.255.

If you want to subnet it, It could be with a mask of /25, /26, etc

192.168.10.0 cannot be assigned as a IP address to any interface (by default settings). The first IP address of a subnet is assigned as the network address and the last as the broadcast address.

192.168.10.0 / 24 is the network addresses.
192.168.10.255 / 24 is the broadcast address

Even if you want to go as per the rule of 2^n – 2 to find the value of the “number of valid hosts” its going to be 2^8 – 2 = 254.
Why do we reduce 2? It because of the network ID and the broadcast ID.

cisco_trouble

192.168.0.0 - 192.168.255.255 private
172.16.0.0 - 172.31.255.255 private
10.0.0.0 - 10.255.255.255 private

patelhari

it is belong to class c address

now u have /24 that means 11111111.11111111.11111111.00000000

here above all bits with 1's is for the network and 0's for host so in that your first address 192.168.10.0 goes for the network and the last 192.168.10.255 for the broadcast.

/24 is all 1's for your more understand and we have rules that we can't use two addresses which are the first address of subnet and last address of subnet which are for the network and broadcast.