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a question on subnetting

Member Posts: 312 ■■□□□□□□□□
okay, im actually studying the CCNA and I need to refresh my memory.

lets say you have a class c address 26 bit mask. So you are going to get a value of 255.255.255.192

192 is (11000000) so the first subnet is going to start with a value of 64

the IP addresses are going to be 65-126? Cause the next network is going to start at 128 and 127 is the broadcast address. Im i correct???
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Member Posts: 676 ■■■□□□□□□□
From the info you provided
XXX.XXX.XXX.1 - 62 = Hosts Address

I could be wrong as I am not the best subnetter (If that is a word).

EDIT: Your calculation is right as well for the 2nd range......just depends on where you start.
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Member Posts: 260
Exactly
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Member Posts: 676 ■■■□□□□□□□
Let's use 192.168.1.10/26
IP Address = 192.168.1.10 or 11000000.10101000.00000001.00001010

Since this is a 26 bit subnet then the 26 left most bits are used to determine the mask which will look like this.
Subnet Mask = 11111111.11111111.11111111.11000000 or 255.255.255.192

Since the subnet mask used 26 bits of our available 32 bits then we will use the remaining 6 bits to calculate the Broadcast Address and Network