jdnagy259 wrote: » Yes the private ip address is 172.30.140/21. The 1st subnet requires 752 hosts, the 2nd requires 100, and the 3rd requires 463. I started with 172.30.0.0/21 and found that it has a magic number of 8. /21 also creates 1024 hosts which is enough to supply the largest subnet (752). Here is my subnetting work. 172.30.0.0 /21- 172.30.7.255/21 I then move to a /22 so that I won't waste as many hosts. /22 = 512 hosts > 463 hosts needed for the third subnet 172.30.8.0/22 - 172.30.11.255 /22 I then move to /24 for the last subnet. 172.30.12.0/24 - 172.30.12.255 The first ten address for subnet number #1 are reserved so that's why I assign the first pc an ip address of 172.30.0.11, because I can't use 172.30.0.1 , 172.30.0.2, 172.30.0.3...etc. Then I just went and assigned any other interface that needed an ip address. Well this is at least my way of thinking haha but I'm pretty sure this is not how all it works? Anyways, I appreciate any help that I can get.