Given IP Address Is Different From The First Network Address (CIDR)

dark525dark525 Registered Users Posts: 3 ■□□□□□□□□□
First, I apologize if this is in the wrong section because I do not know where to post this.

So the given IP address is 192.168.40.60 and what we were taught is that the given IP Adderess is always the address of the first network. But according to the image below, the VLSM Address Range is 192.168.0.0 but the given IP is 192.168.40.60.

Plese click the image to preview.

I was not able to ask this to our teacher since what we have tackled so far are just simple IP addresses like 10.0.0.0 so only the first octet is filled out.

Thanks in advance.

Comments

  • gorebrushgorebrush Member Posts: 2,743 ■■■■■■■□□□
    The clue is the masked bits /14

    That means 14 bits of the subnet are marked as 1, 11111111 11111100 00000000 00000000

    So that x.x.40.x range will be covered in there. I think you still need some help with subnetting :)
  • dark525dark525 Registered Users Posts: 3 ■□□□□□□□□□
    gorebrush wrote: »
    The clue is the masked bits /14

    That means 14 bits of the subnet are marked as 1, 11111111 11111100 00000000 00000000

    So that x.x.40.x range will be covered in there. I think you still need some help with subnetting :)

    I really do. I'm still on the 1st half of my CISCO 2 course :D

    So it doesn't necessarily mean that the given IP address would be the Address of the first network?
  • tecnodog7tecnodog7 Member Posts: 129
    dark525 wrote: »
    So it doesn't necessarily mean that the given IP address would be the Address of the first network?

    If I am understanding you correctly, do you mean to say the first valid host IP of that network? Or does that Ip address x.x.40.x is part of that network?

    I'll just expound of what gorebrush said.

    So the last 1 is our incriment so with that being said that will be our range
    So we get
    192.168.0.0 - 192.171.255.255
    192.172.0.0 - 192.175.255.255
    192.176.0.0 - 192.179.255.255
    192.180.0.0

    You get the point
    So looking at the address 192.168.40.60 is in the network of 192.168.0.0/22
    In that network the network is 192.168.0.0 , bcast is 192.171.255.255
  • dark525dark525 Registered Users Posts: 3 ■□□□□□□□□□
    We already checked our assignment and the x.x.40.x is really the address of the first network.

    The assignment that we had is like this, we were give then x.x.40.x as the given IP Address and 6 networks with each required number of hosts and we have to fill the table out using CIDR-VLSM.
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