Hello everyone,I need a help about one exercises of subnetting.

Host adress:192.168.193.193
Subnet Mask:255.255.255.192

Questions

1)What is the Number of this subnet?
2)Adress of this subnet?
3)Broadcast adress of this subnet?
4)what is the number of the host(192.168.193.193)?

I would like somebody that could explain the resolution of these questions,because I don't understand how is working the subnetting.I started to study since 2 weeks.
ps:I'm sorry if there are some mistakes because I'm not english.

thanks who will respond to my thread.

Find more posts tagged with

Comments

bharvey92

What do you think the answers are to your 4 questions. Post that and we can then explain and guide you onto the right track.

mgmguy1

dextermorgan9494,
Relax. You'll get this. If you have only been studying for 2 weeks I am sure subnetting seems very overwhelming at this point.
Please remember to take it one step at a time. Questions 1,2,3 I can answer but question is worded in a way I am not understanding so I agree with bharvey92 to post the answers from whatever book or site you are getting this form and then we can help you break it down.

dextermorgan9494

The last time my teacher teached me about subnetting and after at the end of the day,she gave to me af homework.
She created by her own

Given an host adress:192.168.193.193 and a subnet mask 255.255.255.192
determine:

a)class of this adress.
b)default subnet mask
c)broadcast adress of this net?
d)subnet's number.
e)subnet's adress
f)broadcast adress of this subnet
g)host's number.

that's exactly her track,naturally I translate from my language

dextermorgan9494

maybe is my problem but I can't succeed to resolve some of this questions.

dextermorgan9494

I can send you as well the photo of her track.But is in italian so I don't think you are able to translate.

Priston

IPv4 subnetting reference - Wikipedia, the free encyclopedia

What do you think the answers are? No one is going to do your homework for you...

dextermorgan9494

I don't want that somebody does my homework,the homework is another one similar to this,but I don't understand the resolution,there aren't enough guide in my language,I'm confused.I don't want link or something else,I want only some directories.

DCD

dextermorgan9494 wrote: »

a)class of this address.
b)default subnet mask
c)broadcast adress of this net?
d)subnet's number.
e)subnet's address
f)broadcast adress of this subnet
g)host's number.

A) Is it a class A or B or C address?
B)default subnet mask What is the subnets for those address?
C)broadcast adress of this net? You have Network ID - First Host to Last Host -- Broadcast address.
D)subnet's number. The formula she gave you
E,F,G) You should be able to get this from the above information.

Once you provide some of the information other will help you out.

dextermorgan9494

Host adress
192.168.193.164/27
subnet mask
255.255.255.224

you can resolve with this other example that gave me the teacher as well.That's the only information that she gaves to me.

Priston

take it one step at a time, what is the subnet class?
Is it in the range of
Class A 0.0.0.0 - 127.255.255.255
Class B 128.0.0.0 - 191.255.255.255
Class C 192.0.0.0 - 223.255.255.255

Jon_Cisco

Welcome to the forum dextermorgan.
As you can see people on this site will help you but you have to first show your attempt.
You will need to understand binary to figure out the subnets. At first it seems complicated but it will become easier.

Some key numbers.
128 - 64 - 32 - 16 - 8 - 4 - 2 - 1
These are the decimal values for the bits in each octet.

255 in binary is 11111111 (add 128+64+32+16+8+4+2+1)
192 in binary is 11000000 (add 128+64)
the subnet mask 255.255.255.192 is written 11111111.11111111.11111111.11000000
the last octet allows you network to create 4 subnets with a class C address range using the first two bits
.0
.64
.128
.192
using the last 6 bits you can create up to 64 numbers which will include your network, hosts, and broadcast.

Good Luck. It will come with practice.

dextermorgan9494

Jon_Cisco wrote: »

Welcome to the forum dextermorgan.
As you can see people on this site will help you but you have to first show your attempt.
You will need to understand binary to figure out the subnets. At first it seems complicated but it will become easier.

Some key numbers.
128 - 64 - 32 - 16 - 8 - 4 - 2 - 1
These are the decimal values for the bits in each octet.

255 in binary is 11111111 (add 128+64+32+16+8+4+2+1)
192 in binary is 11000000 (add 128+64)
the subnet mask 255.255.255.192 is written 11111111.11111111.11111111.11000000
the last octet allows you network to create 4 subnets with a class C address range using the first two bits
.0
.64
.128
.192
using the last 6 bits you can create up to 64 numbers which will include your network, hosts, and broadcast.

Good Luck. It will come with practice.

Thanks Jon_Cisco.
That's is what I made by my own
Host adress
192.168.193.164/27
subnet mask
255.255.255.224
1)The classe is C because is inside a range between 192 and 223
2)Default subnet mask is 255.255.255.0 this as the book says
3)Broadcast?192.168.193.255 you have to add 255 or rather the last host
4)Subnet's number?My teacher told me that is the 5(fifth) subnet why??????I don't understand
5)Subnet's address?192.168.193.160????I don't understand why
6)Broadcast's address?192.193.193.191??I don't know how she solve that-
7)4(fourth) host...why????

A you can see I don't understand how she solve the 4,5,6,7 questions....if somebody could help me I would be very happy.

Jon_Cisco i know as well what you say before

Thanks class c we know N.N.N.H
so

128 64 32 16 8 4 2 1
2⁷2⁶2⁵2⁴2³2²2¹2 ^{0

Example:I wanna create 8 subnet I take 3 bit because}2^{3=8,I wanna create 10 I take 4 bit...}2^{4=16....I take 10 and 6 for expansion}^{other example 24 in binary; 00011000}

Priston

3) Broadcast address = host bits being all 1s
default subnet mask for a class C address 255.255.255.0
nnnnnnnn.nnnnnnnn.nnnnnnnn.hhhhhhhh
11000000.10101000.11000001.11111111
192.168.193.255

6) with the mask 255.255.255.224
nnnnnnnn.nnnnnnnn.nnnnnnnn.nnnhhhhh
11000000.10101000.11000001.10111111
192.168.193.191
the last 5 are host bits and the last 5 are all 1s

5) subnet address would be host bits all 0
nnnnnnnn.nnnnnnnn.nnnnnnnn.nnnhhhhh
11000000.10101000.11000001.10100000
192.168.193.160

7) If 192.168.193.160 is the subnet address, 192.168.193.161 is your first host address

4)You had 255.255.255.0 and you turned it into 255.255.255.224
nnnnnnnn.nnnnnnnn.nnnnnnnn.hhhhhhhh
nnnnnnnn.nnnnnnnn.nnnnnnnn.nnnhhhhh
you have 3 network bits 2³-2 = 6 which means you have 6 networks

With the no ip subnet-zero rule you can't use the first and last subnet https://learningnetwork.cisco.com/thread/32136
nnnnnnnn.nnnnnnnn.nnnnnnnn.nnnhhhhh
11000000.10101000.11000001.00000000
11000000.10101000.11000001.00100000 - first usable subnet
11000000.10101000.11000001.01000000 - 2nd
11000000.10101000.11000001.01100000 - 3rd
11000000.10101000.11000001.10000000 - 4th
11000000.10101000.11000001.10100000 - 5th
11000000.10101000.11000001.11000000 - last usable subnet
11000000.10101000.11000001.11100000