Redhat 7 scripting question

ally_uk

Dear gods of linux is there a one liner I can use to show a ip address of a system and by using awk and cut wizadry cut down the output to show just the ip address

So I can then create a menu driven script that can be used on all systems to show a i.p addr

masq

Hi.
You didn't provide enough info about your systems, whether they're ipv4 or ipv6, number of network interfaces, etc..
But I guess this should work for you:

$ ip addr | grep -Ei "inet.*eth[[:digit:]]" | tr -s " " | cut -f 3 -d " " | cut -f1 -d"/"