Redhat 7 scripting question

ally_uk

Dear gods of linux is there a one liner I can use to show a ip address of a system and by using awk and cut wizadry cut down the output to show just the ip address

So I can then create a menu driven script that can be used on all systems to show a i.p addr

masq

Hi.
You didn't provide enough info about your systems, whether they're ipv4 or ipv6, number of network interfaces, etc..
But I guess this should work for you:

$ ip addr | grep -Ei "inet.*eth[[:digit:]]" | tr -s " " | cut -f 3 -d " " | cut -f1 -d"/"

ally_uk

Hey one network interface using ipv4 ethernet.

Thank you for the reply would also be interesting to see some other solutions perhaps with using awk.

Thats the beauty of Linux so many ways of getting things done.