Subnetting Question

adrianm68adrianm68 Member Posts: 65 ■■□□□□□□□□
Go this one wrong because I looked at the wrong octet and stupidly thought someone would design a network with no hosts. But when I saw the answer, I wanted to get clarification, since I think the total number of hosts per subnet should be 509. There are 9 bits for hosts = 511 ip addresses. Take 2 off for subnet id and broadcast = 509.

Where am I wrong?

2017 Goals: Cisco: [x]Switch [ ]Route [ ]Tshoot

Cisco engineer's command to teach his dog to sit: "no stand"

Comments

  • rob42rob42 Member Posts: 423
    First, note that this is a ‘Class B’ IP and as such the standard Mask (255.255.0.0) would give us 16 bits for the Subnets and 16 bits for the Nodes.

    But, the Mask used is 255.255.254.0 which has allocated an extra 7 bits for the Subnets, therefore 7 bits less for the Nodes.

    16-7 = 9 bits for the Nodes

    2^9 = 512 Nodes, less two = 510.

    2^7 = 128 Subnet.

    {Sorry, that should read "128 Subnets."}
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  • adrianm68adrianm68 Member Posts: 65 ■■□□□□□□□□
    Right. I don't know what I was thinking. For some reason I was adding up block sizes... 1,2,4,8,16,32,64,128, and 256, instead of 9^2
    2017 Goals: Cisco: [x]Switch [ ]Route [ ]Tshoot

    Cisco engineer's command to teach his dog to sit: "no stand"
  • rob42rob42 Member Posts: 423
    adrianm68 wrote: »
    Right. I don't know what I was thinking. For some reason I was adding up block sizes... 1,2,4,8,16,32,64,128, and 256, instead of 9^2


    No problem, (b.t.w it's 2^9, not 9^2)

    It took me a while to get my head around the math, but persistence pays off. :)
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