If a device is assigned the IP address 9.80.86.211 /27 on an interface, the valid subnet address for the interface will be ____________
So a /24 address is 255.255.255.0, this leave you with 3 bits (27-24=3), that's 128+64+32=224. The subnet address should be 255.255.225.224,
- a) 9.80.86.192
- b) 9.80.86.223
- c) 9.80.86.224
- d) 9.80.86.128
There's the answers they give, so I say the answer is
C, Practice Test says no
A is the correct answer, what am I missing?