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Subnet question
Hello all
Stuck on this problem. plz help
[FONT="]What is the network address and subnet mask (in CIDR noration) of the hidden (xxx.xxx.xxx.xxx/xx) subnet? The whole network has a network address and subnet mask of 192.168.0.0/23[/FONT]
[FONT="]The correct answer is:[/FONT]
[FONT="]192.168.1.128/26[/FONT]
[FONT="]The block size for a subnet is 256-subnet mask value. Start at zero and count in block sizes. Every block size will be a new network address. Find the block size of the highest subnet and see what the next block will be.
I am able to understand /26 part but how are they getting the network ID?
Thanks[/FONT]
Stuck on this problem. plz help
[FONT="]What is the network address and subnet mask (in CIDR noration) of the hidden (xxx.xxx.xxx.xxx/xx) subnet? The whole network has a network address and subnet mask of 192.168.0.0/23[/FONT]
[FONT="]The correct answer is:[/FONT]
[FONT="]192.168.1.128/26[/FONT]
[FONT="]The block size for a subnet is 256-subnet mask value. Start at zero and count in block sizes. Every block size will be a new network address. Find the block size of the highest subnet and see what the next block will be.
I am able to understand /26 part but how are they getting the network ID?
Thanks[/FONT]
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damico
Registered Users Posts: 2 ■□□□□□□□□□
Is this a multiple choice? What is the other option? Just to know. -
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NEODREAM
Member Posts: 124 ■■■□□□□□□□
/26 is 255.255.255.192 so your block size is 64, which indicates when each network begins, example:
192.168.1.0 - .63
192.168.1.64 - .127
192.168.1.128 - .191
192.168.1.192 - .255
From the way the question is asked I'm still not too sure what they are wanting, but to answer your question that is why the network starts at the .128 for a /26 in this example.