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Subneting question
wizarddeath
Ok, so Im trying to hone my subnet skills, I can get my head around most if I get them wrong, but looking for some help here.
The question:
Question: You are designing a subnet mask for the 10.0.0.0 network. You want 3000 subnets with up to 3400 hosts on each subnet. What subnet mask should you use?
Answer: 255.255.240.0
My answer was /21
255.255.248 or 11111111.11111111.11111000.00000000
Because 13 network bytes barrowed = 4096 subnets which was the closest to 3k subnets, with more then enough remaining host. Help!
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Comments
dmaftei
With /21 (mask 255.255.248.0) you get 8192 subnets, with 2048 addresses (i.e. 2046 hosts) per subnet.
With /20 (mask 255.255.240.0) you get 4096 subnets, with 4096 addresses (i.e. 4094 hosts) per subnet.
wizarddeath
Grrr stuck in the octet mode, thinking 128 was 8 and not 7..... I see now, thanks.
evanderburg
In other words, 12 bits borrowed is 4096. 12 both ways.
2^10=1024
2^11=2048
2^12=4096
nuglobe
For the CCNA should I know my powers that high like the back of my hand?
Humper
It's really not hard, I remember specifics in the upper range like 2^10 was 1024, so I knew if I needed to know 2^11 then that would be 1024 doubled so 2048....2^12 is 4096...
I would focus mostly on class B and C for the exam.
bernie1442
nuglobe
PostPosted: Tue Jun 20, 2006 10:39 pm Post subject:
For the CCNA should I know my powers that high like the back of my hand?
A trick that I learned that may be usefull to others is just to memorize the 1st 10 powers of 2, this will let you make a failrly close estimate of the higher powers. For example 2^4 = 16.....2^14 = 16,384.
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