IPV6 question.

mgmguy1mgmguy1 Linux Essentials certified , Cisco CCENT certified PA Member Posts: 480 ■■■□□□□□□□
As IPV4 is phased out for IPV6 will becomes the defacto standard, I have a question on how you read an IVP6 adress.

Example. On an IPV4 setup 192.168.5.89. The 192.168 is the system address and 5.89 is the host adress. I have IPV4 down. However. I am haveing a hard time understanding on a IPV6 address.

Useing this Example from the Tech Notes. what part of this address is the system address and which part is the Host address???

FEDC:BA12:ABCD:3210:FEDC:BA98:7654:1234
"A lot of fellows nowadays have a B.A., M.D., or Ph.D. Unfortunately, they don't have a J.O.B."

Fats Domino

Comments

  • EdTheLadEdTheLad Member Posts: 2,111 ■■■■□□□□□□
    Exactly like IPV4, you need the mask to work out the network address.Your example above is also incorrect,192.168.5.89 is a natural class c address with 24 bits for the network.Therefore the network address would be 192.168.5.0, that is assuming its using the natural /24 bit mask.You could have 192.168.5.89/16 (i.e. mask 255.255.0.0) then the network address will be 192.168.0.0, for ipv6 you follow the same rules FEDC:BA12:ABCD:3210:FEDC:BA98:7654:1234/16 would mean
    FEDC:: is the network address.The /16 represents 16 bits of subneting.
    Networking, sometimes i love it, mostly i hate it.Its all about the $$$$
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