IPV6 question.

mgmguy1mgmguy1 PA Member Posts: 485 ■■■■□□□□□□
As IPV4 is phased out for IPV6 will becomes the defacto standard, I have a question on how you read an IVP6 adress.

Example. On an IPV4 setup The 192.168 is the system address and 5.89 is the host adress. I have IPV4 down. However. I am haveing a hard time understanding on a IPV6 address.

Useing this Example from the Tech Notes. what part of this address is the system address and which part is the Host address???

"A lot of fellows nowadays have a B.A., M.D., or Ph.D. Unfortunately, they don't have a J.O.B."

Fats Domino


  • EdTheLadEdTheLad Resident Underachiever Member Posts: 2,111 ■■■■□□□□□□
    Exactly like IPV4, you need the mask to work out the network address.Your example above is also incorrect, is a natural class c address with 24 bits for the network.Therefore the network address would be, that is assuming its using the natural /24 bit mask.You could have (i.e. mask then the network address will be, for ipv6 you follow the same rules FEDC:BA12:ABCD:3210:FEDC:BA98:7654:1234/16 would mean
    FEDC:: is the network address.The /16 represents 16 bits of subneting.
    Networking, sometimes i love it, mostly i hate it.Its all about the $$$$
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