What's 2*80 in Hexa? (AES key expansion Round Key confusion)
shivajikobardan Member Posts: 20 ■■□□□□□□□□
The result is shown to be 1B. How did we get this value?
So, this looks like a case of carry in hexa addition, so how'd we do this calculation?
I'm asking this question because of this. Here' for j=8, Round Constant is 80. The formula to find next round constant is to multiply the current round constant with 2. So, it's 2*80 and should be 100. But it's not the case. So, I want to know how is it done?