I don't understand this question..

nzchuen

3 addresses are shown in binary form below:

A. 01100100.00001010.11101011.00100111
B. 10101100.00010010.10011110.00001111
C. 11000000.10100111.10110010.01000101

Regarding these three binary addresses in the above exhibit; which statements below are correct? (Select three)

A. Address C is a public Class C address.
B. Address C is a private Class C address.
C. Address B is a public Class B address.
D. Address A is a public Class A address.
E. Address B is a private Class B address.
F. Address A is a private Class A address.

Can pls explain to me what is public class and private class?

thanks..

Danman32

private address ranges are:

192.168.x.x/24 class C private address range
172.16.x.x/12 (172.16.x.x - 172.31.x.x) class B private address range
10.x.x.x/8 class A private address range
You can't use these addresses as source or destination addresses directly on the internet. The backbone routers on the internet are supposed to filter these addresses. You have to translate them first using NAT or PAT to valid, registered public internet addresses.

With exception to class D and above, the rest are public addresses.

So the task at hand is to convert the binary octets into decimal, determine the class of the address and if it falls into the address ranges designated as private addresses and should not be thought of as: Address C is a private class, C address.
You could get away with only converting the first two octets, unless the first octet is 10, in which you can stop right there.

Looking over your post again, I think you got confused about the modifier for the term class. Class isn't being applied to public or private, but rather class A, B or C address. Try adding a comma between the word private or public and class, that might make the possible answers clearer.

In other words answer A is can be more clearly written: Address C is a private, class C address and should not be thought of as: Address C is a private class, C address.