Subnetting class A

binarysoulbinarysoul Member Posts: 993
How do you find the subnet # and host ranges for the following?

11.220.100.18, mask 255.255.0.0

11.220.100.18, mask 255.255.128.0

What's the magic number in each case? For the first one, I think you have 254 subnets, but what about the range of each subnet?

I find these two a bit confusing.

Comments

  • EdTheLadEdTheLad Member Posts: 2,111 ■■■■□□□□□□
    binarysoul wrote:
    How do you find the subnet # and host ranges for the following?

    11.220.100.18, mask 255.255.0.0

    11.220.100.18, mask 255.255.128.0

    What's the magic number in each case? For the first one, I think you have 254 subnets, but what about the range of each subnet?

    I find these two a bit confusing.

    Is this what you're looking for?

    11.220.100.18 /16
    host range 11.220.0.1 -> 11.220.255.254

    11.220.100.18 /17
    host range 11.220.0.1 11.220.127.254
    Networking, sometimes i love it, mostly i hate it.Its all about the $$$$
  • binarysoulbinarysoul Member Posts: 993
    Is this what you're looking for?

    11.220.100.18 /16
    host range 11.220.0.1 -> 11.220.255.254

    11.220.100.18 /17
    host range 11.220.0.1 11.220.127.254

    It's right, but which subnet each IP address belongs to? Like some, I can perfectly do subnetting with class B and C, but not as good with A.
  • EdTheLadEdTheLad Member Posts: 2,111 ■■■■□□□□□□
    11.220.100.18 /16

    If you look at it from a class point of view its class A, you have an additional 8 bits of subnetting, subnets are 11.1.x.x -> 11.255.x.x, so the address 11.220.100.18 is in subnet 11.220.0.0

    11.220.100.18 255.255.128.0
    You borrow 9 bits, thrid octet is 100 which is < 128 therefore its in the first
    subnet, 11.220.0.0, if the address you gave was 11.220.160.16 it would be in the second subnet 11.220.128.0
    Networking, sometimes i love it, mostly i hate it.Its all about the $$$$
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