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# subnetting question

Member Posts: 61 ■■□□□□□□□□
Hey guys,

My teacher has assigned us some subnetting homework. I'm stumped on this one. Maybe you guys can give me a hand.

He says to use network 192.168.187.0/28, and assign the 4th subnet and the 6th subnet on interfaces S0/0 and S0/1 respectively.

I gather that the mask is 255.255.255.240 , however I seem to be missing a step in finding the correctly numbered subnets. Any help is greatly appreciated. Thx@!

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Member Posts: 4,884 ■■■□□□□□□□
First subnet is 192.168.187.0.
Second is 192.168.187.16.
Third is 192.168.187.32 so the 4th is...
:
:
:

If you guessed 192.168.187.48 you would be correct. Keep going until you get to the 6th subnet.
Now remember those are the actual subnets, so you have to figure out your first host is going to be 187.1, 187.17, 187.33 and 187.49 respectively. Hope that helps!
All things are possible, only believe.
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Member Posts: 24 ■□□□□□□□□□
Here is what I would do.

Write this down:

/17 /25 .128
/18 /26 .192
/19 /27 .224
/20 /28 .240

/21 /29 .248
/22 /30 .252
/23 .254
/24 .255

Go back and circle /28.
You will get the following.
192.168.187.0/28 = 192.168.187.0 255.255.255.240

256-240 = 16

0 .1 .14 .15
16 .17 .30 .31
32 ... ... ....
48
64
80
96
112
128
...

I did this for awhile until I could do it in my head.
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Member Posts: 127
useful link, just practice and think lil bit...

www.subnettingquestions.com[

cheers