To determine the number of subnets available within an address space, simply calculate
the value of 2y, where y equals the number of bits in the subnet ID.
Because you have allocated 8 bits to the subnet identifier, you can create
up to 254 subnets on this network (28–2=254).
Now my question is why would they tell you to determine the number of subnets one way for one exam and another for the other. Way to go M$!!!
So is 2x-2 the correct way to determine the number of available subnets for the 70-293 but just simply 2x for the 20-291?