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subnetting help

mpca1mpca1 Member Posts: 2 ■□□□□□□□□□
Hey,

found this site using google, and by far has a lot of good information. I am practicing my subnetting, and came across this question, and im having a hard time getting the answer.
The IP address space of 128.107.7.0/24 has been allocated for all devices on this network. All
devices must use the same subnet mask and all subnets are usable.
Which subnet mask is required to apply the allocated address space to the configuration that is
shown?

any ideas how to tackle this?

cheers

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    mpca1mpca1 Member Posts: 2 ■□□□□□□□□□
    I think I might of figured it out,

    /24 so we know that 8 bits are left for the host.
    32-24= 8

    2^n - 2 = how many hosts we need.
    2^8 - 2 = 6, so we need 6 host bits



    if we write out

    255 | 255 | 1 1 1 1 1 1 1 1 | 1 1 0 0 0 0 0 0 |

    /24 + 2 = /26 which ends up being 255.255.255.192

    am I right? if anyone can confirm this?
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    dynamikdynamik Banned Posts: 12,312 ■■■■■■■■■□
    Is that the entire question? It doesn't specify how many hosts you need per subnet or anything like that? What is the "configuration that is shown" that it mentions at the end? Is there a diagram?
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    r_durantr_durant Member Posts: 486 ■■■□□□□□□□
    Yea, I'm with dynamik...Is there a diagram or something, the question did state "...the configuration that is shown?"
    CCNA (Expired...), MCSE, CWNA, BSc Computer Science
    Working on renewing CCNA!
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    shednikshednik Member Posts: 2,005
    Yea I think there is something missing there??
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    NetstudentNetstudent Member Posts: 1,693 ■■■□□□□□□□
    I think the question is trying to get you to figure out what a /24 is. IN which case it would be 255.255.255.0


    That would be the subnet mask entered for all the hosts in that range. You may have overcomplicated the question.

    But it does say 'Configuration that is shown" so who knows.
    There is no place like 127.0.0.1 BUT 209.62.5.3 is my 127.0.0.1 away from 127.0.0.1!
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