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Help with a subnet address

mileage1969mileage1969 Member Posts: 16 ■□□□□□□□□□
I'm having trouble with network addressing question. I've been given the task of subnetting an address of 130.10.0.0/24 to provide 32 hosts per subnet. I need to work out the first 10 subnets, then use the fourth subnet and assign the highest address to a router interface. I cannot use subnet zero. So far I've got the correct subnet mask which is 255.255.255.192 but am stuck to work out the address as I don't know how to get 10 subnets when I'm working in multiples of 64.
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    EmpathyEmpathy Member Posts: 56 ■■□□□□□□□□
    Well you've got the mask figured out correctly, but that's actually a /26, not /24.

    since you're borrowing all 8 bits from the 3rd octet, your block size is one in that octet (256-255). So your first 10 networks (not counting subnet zero) will be:

    130.10.0.64
    130.10.0.128
    130.10.0.192
    130.10.1.0
    130.10.1.64
    130.10.1.128
    130.10.1.192
    130.10.2.0
    130.10.2.64
    130.10.2.128

    The fourth network is 130.10.1.0. Since your block size is 64, your broadcast address will be 130.10.1.63. That makes your last valid host 130.10.1.62.
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    mileage1969mileage1969 Member Posts: 16 ■□□□□□□□□□
    Many thanks Emaphy. I included the /24 mask as it was the given address before being subneted. Now I can move on with the task.
    Save Water - Drink BEER!
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    EmpathyEmpathy Member Posts: 56 ■■□□□□□□□□
    Happy studies!
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