Packet Tracer 4.11 lab

usernouserno Member Posts: 3 ■□□□□□□□□□
Hi All, I do labs in packet tracer 4.11, and I have a question how resolve this exercise icon_confused.gif:

-The local LAN of the new branch office is assigned an IP network address range of: 130.10.0.0/24. This LAN must be subnetted. Each subnet of the Internetwork needs to accommodate 32 host addresses. (Use the smallest subnet mask available that still provides for the 32 hosts per subnet.) Determine the first 10 subnets available. Use the fourth usable subnet for the LAN connected to SWA (LAN subnet). Do NOT count subnet zero as the first subnet.

The Ethernet interface connected to Boaz connecting to SWA is assigned the highest usable address within the LAN subnet.

For security reasons, the IP addresses of the Hosts on the LAN subnet are split in two groups. The production workstations will be assigned the lower half of the IP addresses from the fourth subnet. The network devices and management stations will be assigned the upper half of the IP addresses from the fourth subnet. The decision bit for determining upper and lower host device IP addresses is the bit directly after the last subnet bit. Example: if the subnet mask is 240, the first 4 bits indicate the subnet, the 5th bit will determine if the host falls within the lower range or upper range of hosts (where 0 indicates lower range and 1 indicates upper range).

PC0 simulates a production host. The IP address of this host is the first IP address within the lower range of the IP addresses. PC1 simulates a management host. The IP address of this host is the first IP address within the upper range of IP addresses.

This is lab "SkillBuilder_CCNA2HandsonFinal", Packet tracer 4.11 icon_rolleyes.gif

Comments

  • miller811miller811 Member Posts: 897
    If we told you how to do it you would not learn anything. :P

    If you know subnetting, you can easily figure this one out.

    If you don't know subnetting, you will need to go back and learn it, because you will need to be able to do it quickly (in your head is preferred) to be able to pass the CCNA.
    I don't claim to be an expert, but I sure would like to become one someday.

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  • usernouserno Member Posts: 3 ■□□□□□□□□□
    miller811 wrote:
    If we told you how to do it you would not learn anything. :P

    If you know subnetting, you can easily figure this one out.

    If you don't know subnetting, you will need to go back and learn it, because you will need to be able to do it quickly (in your head is preferred) to be able to pass the CCNA.

    It's true, but can I please some advice how can I resolve this exercise step by step, I would like to learn subnetting. :)

    What should I do first?
  • dynamikdynamik Banned Posts: 12,312 ■■■■■■■■■□
    You could start with something like this: http://www.learntosubnet.com/

    It's not hard once you get the hang of it, but it's a somewhat involved process. It's not something we can just teach you quickly.
  • nelnel Member Posts: 2,859 ■□□□□□□□□□
    You could start with something like this: http://www.learntosubnet.com/

    This is a good website to learn subnetting. personally i am not very good with numbers and for some reason struggle when come to doing so. i picked up the wendell odom books for the exam and have learnt to subnet quite easily using his decimal process in the book.

    btw there are several methods to learn subnetting so choose one which suits you best. The decimal one done it for me.
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  • usernouserno Member Posts: 3 ■□□□□□□□□□
    At first I did something like that:

    IP: 130.10.0.0
    Mask: 255.255.255.0

    10000010.00001010.00000000.00000000
    11111111.11111111.11111111.00000000
    Network 10000010.00001010.00000000.00000000
    130.10.0.0


    Number of network bits=16
    Number of hosts bits=8
    Number of subnets bits=8
    Number of hosts per subnet=2^8-2=254
    Number of subnets=2^8-2=254
  • miller811miller811 Member Posts: 897
    Userno - check your private messages.
    I don't claim to be an expert, but I sure would like to become one someday.

    Quest for 11K pages read in 2011
    Page Count total to date - 1283
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