Hi Guys,
Can you just confirm if I have this question (that I set myself) correct?
Q. Subnet 172.16.0.0 to address the below network using the most efficient addressing possible

I have come up with the following VLSM's:
172.16.1.0 - 172.16.1.127 /17 Network for 113 users
172.16.1.128 - 172.16.254 /17 Network for 93 users
172.16.2.0 - 172.16.2.31 /19 Network for 16 users
172.16.2.32 - 172.16.2.35 /30 Network for Wan Link
172.16.2.36 - 172.16.2.39 /30 Network for Wan Link
172.16.2.40 - 172.16.2.43 /30 Network for Wan Link
I think this is right, but just wanted to make sure incase I have done anything daft.
Many Thanks
Nick