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0Day wrote: » Route Selection in Cisco Routers - Cisco Systems I found this at Cisco site, the section, "Making Forwarding Decisions" Is what you need, I think... Oh and what answer are you getting for this question?
Camster187 wrote: » I've been working through the CCNA exam cram third edition its been a great read for the most part and I'm almost confident enough to take my exam. However I am struggling with one of the examples in the book it just simply does not make sense, if anyone can help explaining it I would much appreciate it:The longest prefix match is the best Simplified IP route table 172.16.8.0/24 via 192.168.0.1, Ethernet 0 172.16.10.0/30 via 192.168.0.1, Ethernet 0 172.16.10.64/26 via 192.168.1.1, Ethernet 1 172.16.10.0/24 via 192.168.2.1, Ethernet 2 0.0.0.0/0 via 24.16.5.65, Serial 0 Assume a packet has arrived at router with destination IP 172.16.10.131. Would it be possible for someone to give me a detailed explanation on the right route and why the other summarised routes are not correect. I have tried to work this out with the example in the book and it just doesn't match up. Thanks oin advance.
Camster187 wrote: » Thanks for the link the example on their regarding forwarding decisions makes perfect sense, however here is what the book says regarding my original question:The second,third and fourth all match for their respective prefix length of /28,/26 and /24. The fifth entry is a default route that matches any address but with a /0 prefix.All entries are valid but the one with the longest prefix length match - 172.16.10.128/28 is chosen as best. The router switches the packet out of ethernet 0. Apparently it the packet should be leaving ethernet 0 from a /28 network? I simply cannot work out how. I don't think it is leaving from the 172.16.8.0/24 address because that is not a summarised network (i think). However on working out the 172.16.10.0/30 I can only find the addresses 172.16.10.1 - 172.16.10.4.
172.16.8.0/24 via 192.168.0.1, Ethernet 0 172.16.10.0/30 via 192.168.0.1, Ethernet 0 172.16.10.64/26 via 192.168.1.1, Ethernet 1 172.16.10.0/24 via 192.168.2.1, Ethernet 2
172.16.10.0/24 via 192.168.2.1, Ethernet 2
chmorin wrote: » I'm going to break this down... Router gets a packet with a destination IP address of 172.16.10.131. The router checks its routing table for matching routes. From a routing table of 172.16.8.0/24 via 192.168.0.1, Ethernet 0 172.16.10.0/30 via 192.168.0.1, Ethernet 0 172.16.10.64/26 via 192.168.1.1, Ethernet 1 172.16.10.0/24 via 192.168.2.1, Ethernet 2 only 172.16.10.0/24 via 192.168.2.1, Ethernet 2 is a matching route for that host address. 172.16.8.0/24 has a host range of 8.1-8.254 which does not match 10.131. 172.16.10.0/30 has a host range of 10.1-10.2 which does not match 10.131 172.16.10.64/26 has a host range of 10.65-127 which does not match 10.131. 172.16.10.0/24 has a host range of 10.1-10.255 which does match 10.131. That being said, you contradicted yourself in the proper solution. If 172.16.10.128/28 was part of the routing table, it was a range of 10.129-142, which does match 10.131 and would be a better pick than the 172.16.10.0/24 match on the basis of longer prefix length. Please create a situation that does not involve contradiction if you want a better answer than that.
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