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How do I find the subnet with lack of info..?

sthompson86sthompson86 Member Posts: 370
Hello all, I have ran across something tonight while taking practice test.

There was a scenario with a network diagram, and I was supposed to figure out what the Subnet prefix of a certain LAN was. Normally this is easy easy for me when I have enough info to work with, but in this question I was lost.

I was given 2 IP addresses:

192.168.10.100 and 192.168.10.122

From that I was supposed to figure out that it was a /26 or 255.255.255.192

________________________________________________________

Maybe I just went blank, but I sure do not have a clue on how they got that answer. I have searched Google on how to figure this out but there is soo much generalized stuff out there about subnetting basics that its hard to find exactly what I am looking for.

- Thanks in advanced. - Shane
Currently Reading: Again to Carthage - CCNA/Security

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    Forsaken_GAForsaken_GA Member Posts: 4,024
    Any chance you can post the diagram?
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    sthompson86sthompson86 Member Posts: 370
    Well I did start to, but its from the Boson Practice exams, and I know how some people on here are really ticky when it comes to showing copyrighted stuff.

    Basically what the diagram was was a Router with a LAN connected to it. 192.168.10.100 was the router interface and 192.168.10.122 was the IP address of the host.

    I am used to seeing more info like /24 /26 or 255.255.255.192 etc, which give me some working room to figure out what subnet the IP address range is on.

    But this question only had 2 IP addresses with no subnet info, and the question was wanting to know what Prefix the 2 IP addresses belonged 2 - I am lost lol

    Thanks
    Currently Reading: Again to Carthage - CCNA/Security
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    Forsaken_GAForsaken_GA Member Posts: 4,024
    Well, it's kind of hard to tell without the full context hehe. It's possible it was a bad question, it's also possible that the diagram or the text of the question had a hint.
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    docricedocrice Member Posts: 1,706 ■■■■■■■■■■
    I had a question like this in an interview for a desktop support position back in 2000. It was basically, "Given two addresses, determine the most restrictive subnet mask." I had no clue how to perform that back then.

    If that's what the question is implying, then I can see where they're coming from.
    Hopefully-useful stuff I've written: http://kimiushida.com/bitsandpieces/articles/
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    impzimpz Users Awaiting Email Confirmation Posts: 113 ■■■□□□□□□□
    Hello all, I have ran across something tonight while taking practice test.

    There was a scenario with a network diagram, and I was supposed to figure out what the Subnet prefix of a certain LAN was. Normally this is easy easy for me when I have enough info to work with, but in this question I was lost.

    I was given 2 IP addresses:

    192.168.10.100 and 192.168.10.122

    From that I was supposed to figure out that it was a /26 or 255.255.255.192

    ________________________________________________________

    Maybe I just went blank, but I sure do not have a clue on how they got that answer. I have searched Google on how to figure this out but there is soo much generalized stuff out there about subnetting basics that its hard to find exactly what I am looking for.

    - Thanks in advanced. - Shane

    From what I understand from the info provided, I think that you need to find a subnet mask where the the 2 IP addresses would be valid hosts in.

    /24 /25 /26 /27 would be correct and I'm assuming the /24 /25 /27 wasnt in the possible choices ? ...... or there is a bit more info to eliminate /24 /25 and /27?
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    mella060mella060 Member Posts: 198 ■■■□□□□□□□
    The only possible subnet masks that you could use would be /24 /25, /26 or /27. But you can probably rule out a /24 or /25 mask since the question most likely wants a more specific mask to be used. A /27 mask, which is the most specific mask that includes the two addresses is probably the answer that they are after.

    A /26 would include 62 possible host addresses

    192.168.10.64 would be the subnet address

    The host range would be 192.168.10.65 - 126

    A /27 would include 30 possible host addresses

    192.168.10.96 would be the subnet address

    The host range would be 192.168.10.97 - 126
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    sthompson86sthompson86 Member Posts: 370
    docrice wrote: »
    I had a question like this in an interview for a desktop support position back in 2000. It was basically, "Given two addresses, determine the most restrictive subnet mask." I had no clue how to perform that back then.

    If that's what the question is implying, then I can see where they're coming from.

    Thats exactly what it was asking lol
    Currently Reading: Again to Carthage - CCNA/Security
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    sthompson86sthompson86 Member Posts: 370
    mella060 wrote: »
    The only possible subnet masks that you could use would be /24 /25, /26 or /27. But you can probably rule out a /24 or /25 mask since the question most likely wants a more specific mask to be used. A /27 mask, which is the most specific mask that includes the two addresses is probably the answer that they are after.

    A /26 would include 62 possible host addresses

    192.168.10.64 would be the subnet address

    The host range would be 192.168.10.65 - 126

    A /27 would include 30 possible host addresses

    192.168.10.96 would be the subnet address

    The host range would be 192.168.10.97 - 126

    Thank you sir.
    Currently Reading: Again to Carthage - CCNA/Security
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