Hi guys,
I'm getting a bit confused about how a route can become a feasible successor. From what I've read numerous times, the rule is that the AD(advertised distance or reporting distance) of the route must be "LESS" than the FD(feasible distance) of the successor route.
The reason for my confusion is that I've taken some practice exams where they say the definition is "LESS THAN OR EQUAL TO" modifying what I originally wrote above.
Example:
R1# show ip eigrp topology
IP-EIGRP Topology Table for AS(1)/ID(172.31.16.1)
Codes: P - Passive, A - Active, U - Update, Q - Query, R - Reply,
r - reply Status, s - sia Status
P 172.31.151.0/24, 1 successors, FD is 768
via Connected, Loopback1
P 172.31.211.0/24, 1 successors, FD is 1024
via 172.31.11.201 (1024/760), FastEthernet0/0
P 172.31.24.0/30, 1 successors, FD is 768
via 172.31.11.2 (768/512), FastEthernet0/0
via 172.31.14.2 (1024/512), Serial0/0.4
! Lines omitted for brevity
From what I can see, only 172.31.14.2 can become feasible successor since it's AD=512 which is less than the successor's FD=768.
Can anyone confirm this?
