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Please help me :(

PhoenixJamesPhoenixJames Registered Users Posts: 3 ■□□□□□□□□□
Hello, I just stumbled across this site while doing some research for an assignment. I know this might sound really basic but i've just started a foundation degree involving cisco networking. I'll try to explain my problem as best I can, but please bear with me cos even my terminology may be well off :) lol Also please see the link below to a screen shot of my network.

My Network

My problem is i'm unsure about how to go about allocating the right ip address to each serial cable between each router?

My network is 200.10.204.0/24, and each subnet a 32 network.


My IP addressing scheme is as follows:-



R1
x.x.x.33
PC1
x.x.x.34



x.x.x.65
PC2
x.x.x.66


R2
x.x.x.97
PC3
x.x.x.98



x.x.x.129
PC4
x.x.x.130


R3
x.x.x.161
PC5
x.x.x.162



x.x.x.193
PC6
x.x.x.194




So now that i'm this far, im not sure how to go to the next bit??? my apologies if my problem isnt explained correctly... im new to this.

Comments

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    ccnxjrccnxjr Member Posts: 304 ■■■□□□□□□□
    Methinks first off the mask for the WAN links should be /30 not /32
    Also consider how many hosts per subnet, or should they be divided equally.
    This would be better suited under the CCNA/CCENT forum, but doesn't bother me (no, really, it doesn't, at all )
    :P
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    MonkerzMonkerz Member Posts: 842
    Your subnetting is fine. You will be using a mask of 255.255.255.224 for the "32" networks you have created. You can use the following for your WAN connections if you like:

    Sunderland interface to Newcastle 200.10.204.1/30
    Newcastle interface to Sunderland 200.10.204.2/30
    Sunderland interface to South Shields 200.10.204.5/30
    South Shields interface to Sunderland 200.10.204.6/30
    South Shields interface to Newcastle 200.10.204.9/30
    Newcastle interface to South Shields 200.10.204.10/30
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    PhoenixJamesPhoenixJames Registered Users Posts: 3 ■□□□□□□□□□
    wow fast reply... thank so much that really helped, and glad to know i didnt go wrong with my subnetting :)

    ps i did look in all the topics to see if i could find the right place to post this, but like i said, im really just starting out, might sound daft but my expertise is in software mainly i just have to cover this in my course. at this stage CCNA/CCENT means nothing to me, i know ccna is a big exam icon_lol.gif

    cheers for the help guys
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    PhoenixJamesPhoenixJames Registered Users Posts: 3 ■□□□□□□□□□
    How did you come up with the /30?

    Did you just divide subnet0 (x.x.x.1 to x.x.x.30) into smaller pieces to accomodate two IP Addresses? (2 for each serial cable)?

    in other words borrowing 6 bits from the network portion leaving two host bits to use for the two IP addresses for each serial cable?

    Like i said, im really just starting out, sorry if im bein a pain in the butt. I'm just starting to get a grasp of things. but im serious about it. How did you come up with that answer?
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    ccnxjrccnxjr Member Posts: 304 ■■■□□□□□□□
    A /30 netmask leaves you with two usable IP addresses,
    Keep in mind that a /30 really means that the firs 30 bits define the network ID, and mean there are only 2 bits at the end to be used as host addresses .
    Netmask: 1111 1111.1111 1111.1111 1111.1111 1100
    Network : xxxx xxxx.xxxx xxxx.xxxx xxxx.xxxx xx00
    1st IP: xxxx xxxx.xxxx xxxx.xxxx xxxx.xxxx xx01
    2nd IP : xxxx xxxx.xxxx xxxx.xxxx xxxx.xxxx xx10
    Broadcast: xxxx xxxx.xxxx xxxx.xxxx xxxx.xxxx xx11
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    powerfoolpowerfool Member Posts: 1,666 ■■■■■■■■□□
    ccnxjr wrote: »
    A /30 netmask leaves you with two usable IP addresses,
    Keep in mind that a /30 really means that the firs 30 bits define the network ID, and mean there are only 2 bits at the end to be used as host addresses .
    Netmask: 1111 1111.1111 1111.1111 1111.1111 1100
    Network : xxxx xxxx.xxxx xxxx.xxxx xxxx.xxxx xx00
    1st IP: xxxx xxxx.xxxx xxxx.xxxx xxxx.xxxx xx01
    2nd IP : xxxx xxxx.xxxx xxxx.xxxx xxxx.xxxx xx10
    Broadcast: xxxx xxxx.xxxx xxxx.xxxx xxxx.xxxx xx11

    This.

    Great explanation.
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